Correct Answer:Option A. 0.01
Solution:This is a problem of statistics and uses the concept of normal distributions. We need to convert the score of 90 into z-score and then find the desired probability from standard normal distribution table.
Converting 90 to z-score:
Now we are to find the probability of z score being more than 2.33. From the z-table the probability comes out to be 0.01.
Therefore, we can conclude that the probability of class average is greater than 90 is 0.01.
Answer:
X=16.5
Step-by-step explanation:
17.54167
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Answer:
24, 21, 15, 12
Step-by-step explanation:
Since x is given in the table, you can find the y-values by plugging each of the x-value into the equation replacing x.
The answer would be 37 r. 9