Question

Each container has a base of 4 1/4 yds by 1 2/3 yds. What is the area covered by all the containers?

Answer 1

Answer:

See Explanation

Step-by-step explanation:

Given

Base Dimension

$Length = 4\frac{1}{4}yd$

$Width = 1\frac{2}{3}yd$

Required

The base area of all containers

First, calculate the base area of 1 container.

This is calculated as:

$Area = Length * Width$

$Area = 4\frac{1}{4}yd * 1\frac{2}{3}yd$

Express as improper fraction

$Area = \frac{17}{4}yd * \frac{5}{3}yd$

So, we have:

$Area = \frac{17*5}{4*3}yd^2$

$Area = \frac{85}{12}yd^2$

The number of containers is not given. So, I will use 'n' as the number of containers.

So, we have:

$Total = n * Area$

$Total= n * \frac{85}{12}yd^2$

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Assume n is 3 (i.e. 3 containers)

The total area is:

$Total= 3 * \frac{85}{12}yd^2$

$Total= \frac{85}{4}yd^2$

$Total= 21\frac{1}{4}yd^2$

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