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natulia [17]
3 years ago
10

12xy if x=5 and y=-3

Mathematics
2 answers:
iragen [17]3 years ago
4 0

12 times 5 times -3 = -180

Gemiola [76]3 years ago
3 0

<em>Answer,</em>

<h2>-180</h2>

<em>Explanation,</em>

All they are asking you to do is input the 5 for the x and the -3 for the y in the equation

<em>Input the numbers</em>

12 x 5 x -3 = <em>-180</em>


<u>Hope this helps :-)</u>

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<u>Question:</u>

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

<u>Answer:</u>

The number of real solutions for the equation x^{2}+5 x+7=0 is zero

<u>Solution:</u>

For a Quadratic Equation of form : a x^{2}+b x+c=0  ---- eqn 1

The solution is x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  

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On comparing Equation (1) and Equation(2), we get

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In x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} , b^2 - 4ac is called the discriminant of the quadratic equation

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Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

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D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

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