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telo118 [61]
3 years ago
11

What is the circumference and area of this circle? (Use 3.14 for pi)

Mathematics
1 answer:
mr Goodwill [35]3 years ago
4 0

Answer: Circumference = 37.7

Area= 113.1

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Can somebody please help me with these questions bc i dont get them
Ksju [112]

Answer:

1) No, the sum isn't equal to 180

2) Yes, the sum is equal to 180

3) No, the sum isn't equal to 180

4) Yes, the sides follow the triangle inequality

5) Yes, the sides follow the triangle inequality

6) Yes, it's an equilateral triangle

7 0
3 years ago
Read 2 more answers
Unit 11 Homework 1: Area of Plane Figures
iren2701 [21]

Answer: 4. 432 cm^2/2 = 216 cm^2

6. 309.76 mm^2

8. pi * 22^2 = 484pi (or, approximately 1,519.76) in^2

484/2 = 242pi or 759.88 in^2.

10. 297.84 in^2/2 = 148.92 in^2

Step-by-step explanation:

To find the area of a triangle, you take the base and multiply by the height, and then divide by 2. Hence giving me the answers I obtained in #4 and #10.

A square is equal on all sides, so you would just square the measurement of the one side.

To find the area of a circle, you would do pi times the radius^2. Since this is a semicircle, you actually should divide the number you got by 2. (Which is why I did so up above).

4 0
3 years ago
Read 2 more answers
Ms.Chen wants to pirchase sets of christmas lights to decorate her house. The lights cost $13 per package. She has saved $360 fo
aleksklad [387]
It is too blurry I cant see anything can you just ask the question instead of taking a picture
8 0
3 years ago
A boat leaves Port A and travels due east. Port B is 15 mi due north of Port A, and Port C is 24 mi due south of Port A. The boa
sesenic [268]
With this problem, we have two right triangles meaning we will end up using the Pythagorean Theorem. For the sake of the problem, let's say the boat is at point D. The two triangles we have are ΔACD and ΔABD. Let's first go through and define the lines.

Let's start with ΔACD:
Port A is 24 miles from Port C so AC = 24mi. We will represent this as line a
Port C is 25 miles from Boat D so CD (the hypotenuse) = 25mi. We will represent this as line c
We do not know the distance between Port A and Boat D (AD also known as line b) so let's calculate that since we will need it at the end.

We can calculate line b's length using the theorem: a² + b² = c²
a = 24mi
b = ?
c = 25mi

So

(24)² + b² = (25)²
576 + b² = 625
Subtract 576 from both sides to isolate b²

576 + b² - 576 = 625 - 576
b² = 49
Now take the square root of both sides

√b² = √49
b = 7 miles.
Now we know that the distance between Port A and Boat D is 7 miles.

Now let's move on to ΔABD
Port B is 15 miles from Port A so AB = 15mi. We will represent this as line a
Boat D is 7 miles from Port A so AD = 7mi. This will still be line b
We do not know the distance between Port B and Boat D (BD also known as line c).

Time to use the Pythagorean Theorem once more!
a² + b² = c²
15² + 7² = c²
225 + 49 = c²
274 = c²
Take the square root of both sides

√274 = √c²
c ≈ 16.6mi when we round to the nearest tenth

So the distance between Port B and the boat is 16.6 miles


4 0
3 years ago
Which of these is scientific notation?
Vlad [161]

Answer:

1.2×10^3

Step-by-step explanation:

so there it is

8 0
3 years ago
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