Numbers from what we choose will be
62,63,64,65,66,67,68,69,70,....100,101,102,103,104,105,106
multiple of 5 are
65,70,75,80,85,90,95,100,105
multiples of 3 and 5
75,90,105
multiples of 3,5,9
90
Explanation:
Differentiating the solution, we have ...
y' = c1 +8c2x^7
y'' = 56c2x^6
Putting this into the DE, we have ...
x^2y'' -8xy' +8y = 16 . . . . . . . different from your problem statement
x^2(56c2x^6) -8x(c1 +8c2x^7) +8(c1x +c2x^8 +2) = 16
56c2x^8 -8c1x -64c2x^8 +8c1x +8c2x^8 +16 = 16
x^8(56c2 -64c2 +8c2) +x(-8c1 +8c1) +16 = 16
0 +16 = 16 . . . . QED
Let's solve for d:
g=qd+hd
Step 1: Flip the equation.
dh+dq=g
Step 2: Factor out variable d.
d(h+q)=g
Step 3: Divide both sides by by h+q
d(h+q)/h+q=g/h+q
Answer:
d=g/h+q
