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andrezito [222]
3 years ago
10

I hate geometry if someone could help me i would appreciate it so much

Mathematics
1 answer:
Valentin [98]3 years ago
5 0

Answer:

Step-by-step explanation:

150 + 150 + x = 360

x = 60

∠ADC = 60°

they are the same

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Write a rule to describe the transformation.
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1.) Reflect across x-axis

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3.) Move to the right by one unit

Step-by-step explanation:

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3 years ago
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aleksandrvk [35]

Answer:

17. m=-1/2

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Step-by-step explanation:

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3 years ago
X+2y=8 under it is x-3y =6 solve it using simultaneous equation,substitution method.​
cupoosta [38]

Answer:

Step-by-step explanation:

x +2y = 8  ----- (I)

 x = 8 - 2y

x - 3y = 6 -------(II)

Substitute x = 8 - 2y in equation (II)

8 - 2y - 3y = 6    {add like terms}

8 - 5y = 6

Subtract 8 form both sides

 -5y = 6- 8

 -5y = -2

Divide both sides by -5

 -5y/-5 = -2/-5

y = 2/5

Substitute y = 2/5 in equation (I)

x+2*\frac{2}{5}=8\\\\x+\frac{4}{5}=8\\\\x=8- \frac{4}{5}\\\\x=\frac{8*5}{1*5}-\frac{4}{5}\\\\x=\frac{40}{5}-\frac{4}{5}\\\\x=\frac{36}{5}

x = 36/5

8 0
3 years ago
Plz solve this question​
Mkey [24]

\huge \boxed{\mathbb{QUESTION} \downarrow}

  • Simplify ⇨ 1/x(x+a) + 1/x(x-a)

\large \boxed{\mathbb{ANSWER \: WITH \: EXPLANATION} \downarrow}

\sf\frac { 1 } { x ( x + a ) } + \frac { 1 } { x ( x - a ) } \\

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x\left(x+a\right) and x\left(x-a\right) is x\left(x+a\right)\left(x-a\right). Multiply \frac{1}{x\left(x+a\right)} times \frac{x-a}{x-a}. Multiply \frac{1}{x\left(x-a\right)} times \frac{x+a}{x+a}.

\sf\frac{x-a}{x\left(x+a\right)\left(x-a\right)}+\frac{x+a}{x\left(x+a\right)\left(x-a\right)}  \\

Because \frac{x-a}{x\left(x+a\right)\left(x-a\right)} and \frac{x+a}{x\left(x+a\right)\left(x-a\right)} have the same denominator, add them by adding their numerators.

\sf\frac{x-a+x+a}{x\left(x+a\right)\left(x-a\right)}  \\

Combine like terms in x-a+x+a.

\sf\frac{2x}{x\left(x+a\right)\left(x-a\right)}  \\

Cancel out x in both the numerator and denominator.

\sf\frac{2}{\left(x+a\right)\left(x-a\right)}  \\

Expand \left(x+a\right)\left(x-a\right).

\boxed{\boxed{ \bf\frac{2}{x^{2}-a^{2}}}}  \\

3 0
3 years ago
What is four sixths minus five sixths
Veseljchak [2.6K]
1 sixths would be the awnser you just take away four from five that will give you one so you just need to add the sixths part
7 0
3 years ago
Read 2 more answers
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