Answer:
domain: {x | x is a real number}
range: {y l y> -8}
Step-by-step explanation:
f(x) = 4x² – 8 is a parabola, a U shape.
Since the stretch factor, 4, is positive, it opens up, there it will have a minimum value, the lowest point in the parabola.
y > -8 because the minimum is -8.
Parabolas do not have restricted "x" values. "4" does not restrict x because it is the stretch factor, which determines how wide the parabola is.
Quadratic standard form:
f(x) = ax² + bx + c
"a" represents how wide the graph is. If it's negative it opens down, if it's positive it opens up.
"b", if written, tells you it is not centred on the y-axis. It is not written, so the vertex is on the y-axis.
"c" is the y-intercept. In this case, since b = 0, it is also the minimum value.
Answer:
What do think the answer is cause I don't know
For 19, you would do 6b+8b=175, 14b=175, b=12.5. YZ would be 8b=YZ, 8*12.5=YZ, 100=YZ.
Answer:
There is no variable factor common to 24a and 6
Step-by-step explanation:
First number = 24a
Other number = 6
Pime factorisation of 24a = 2×2×3×2×a
Pime factorisation of 6= 3×2
Common factors = 6
Hence, there is no variable factor common to 24a and 6, Other common factor is 6.
