here u go! i hope this is correct :)
Not for sure but it’s most like 6/9
Answer:
We have x^3^2 which is x^3*2 = x*6 times x*4 which is x*10
Hope this helped and brainliest please
Answer:
56% ≤ p ≤ 70%
Step-by-step explanation:
Given the following :
Predicted % of votes to win for candidate A= 63%
Margin of Error in prediction = ±7%
Which inequality represents the predicted possible percent of votes, x, for candidate A?
Let the interval = p
Hence,
|p - prediction| = margin of error
|p - 63%| = ±7%
Hence,
Upper boundary : p = +7% + 63% = 70%
Lower boundary : p = - 7% + 63% = 56%
Hence,
Lower boundary ≤ p ≤ upper boundary
56% ≤ p ≤ 70%
90% of <span>£41 = 90/100 × 41 = </span><span>£36.9
</span>£41 decreased by 90% = 41 - 36.9 = <span>£4.1</span>
