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shusha [124]
3 years ago
13

3in = Feet I need to understand how to convert this to fractions

Mathematics
2 answers:
Vinil7 [7]3 years ago
8 0
A foot is 12 in so a fraction could be 3/12
gizmo_the_mogwai [7]3 years ago
8 0
3/12 or 1/4 of a foot
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XD clan is amazing and thanks guys
Lorico [155]
The answer would be 4
6 0
3 years ago
What does the remainder theorem conclude given that f(x)x+3 has a remainder of 11?
Slav-nsk [51]

By the remainder theorem of polynomial division, the complete equation is f(-3) = 11

<h3>How to complete the blanks?</h3>

The equation is given as:

f(x)/x + 3

Set the divisor to 0

x + 3 = 0

Solve for x

x = -3

Given that the quotient has a remainder of 11.

It means that:

f(-3) = 11

Hence, the complete equation is f(-3) = 11

Read more about remainder theorem at:

brainly.com/question/13328536

#SPJ1

5 0
2 years ago
Find a formula for the inverse of the function. f(x)=1-2/x^3.
Elena-2011 [213]
       f(x) = 1 - ²/ₓ₃
          y = 1 - ²/ₓ₃
          y = 1 - ²/ₓ₃
      y - 1 = ⁻²/ₓ₃
      x - 1 = -2/y³
 y³(x - 1) = -2
         y³ = ⁻²/ₓ₋₁
          y = ∛⁻²/ₓ₋₁
          y = -∛(2x² - 4x + 2)/x - 1
      f⁻¹(x) = -∛(2x² - 4x + 2)/x - 1
4 0
3 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α = 8 per hour, so that the number o
Ksenya-84 [330]

Answer:

Step-by-step explanation:

Step1:

We have Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α =8 per hour, so that the number of arrivals during a time period of t hours is a Poisson rv with parameter μ = 8t

Step2:

Let “X” the number of small aircraft that arrive during time t and it follows poisson distribution parameter “”

The probability mass function of poisson distribution is given by

P(X) = , x = 0,1,2,3,...,n.

Where, μ(mean of the poisson distribution)

a).

Given that time period t = 1hr.

Then,μ = 8t

             = 8(1)

             = 8

Now,

The probability that exactly 6 small aircraft arrive during a 1-hour period is given by

P(exactly 6 small aircraft arrive during a 1-hour period) = P(X = 6)

Consider,

P(X = 6) =  

              =  

              =  

              = 0.1219.

Therefore,The probability that exactly 6 small aircraft arrive during a 1-hour period is 0.1219.

1).P(At least 6) = P(X 6)

Consider,

P(X 6) = 1 - P(X5)

                = 1 - {+++++}

                = 1 - (){+++++}

                = 1 - (0.000335){+++++}

                = 1 - (0.000335){1+8+32+85.34+170.67+273.07}

                = 1 - (0.000335){570.08}

                = 1 - 0.1909

                = 0.8090.

Therefore, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8090.

2).P(At least 10) = P(X 10)

Consider,

P(X 10) = 1 - P(X9)

                 = 1 - {+++++

5 0
3 years ago
PLEASE HELP ME OUT CCCCCCCCCCCCCCCCCC;
IRINA_888 [86]

Answer:

I think it's the last to they sound way more independent!!!

6 0
3 years ago
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