3 over 20 is the fraction in simplest form.
Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
Answer:
Step-by-step explanation:
If you can present a problem in Latex, you can do anything. I don't know what the question mark is for. I'm just ignoring it.
55 2/3 * 66 5/6
One of the ways to get the answer is to use decimals
55.666666667 * 66.833333333 = 3720.38889
Another way to do this problem is to break up one of the numbers
55 2/3 (66 + 5/6) You can do this if you know how to use the distributive property.
55 2/3 * 66 + 55 2/3 * 5/6
( (165 + 2) / 3) * 66 + (165 + 2)/3 * 5/6
167/3 * 66 + 167 / 3 * 5/6
167 * 22 + (167 * 5 / (3 * 6)
3674 + 835 / 18
3674 + 46 7/18
3720 7/18
If none of these seem right and you have choices, please list them.
Answer:
the answer is d
Step-by-step explanation:
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Answer:
1
Step-by-step explanation: