Question

Algebra 2 test help please

Answer 1

Answer

0

Step-by-step explanation:

Let the length be l

We know that,

$Perimeter= 8\sqrt{8} \\Width = 4 \sqrt{2} \\As\ Perimeter = 2(l+b)\\\\8\sqrt{8}=2(l+4 \sqrt{2})\\8\sqrt{8}=2l+8 \sqrt{2}\\8\sqrt{8} -8\sqrt{2}=2l\\4(\sqrt{8} -\sqrt{2})=l\\4(2\sqrt{2} -\sqrt{2})=l\\4(\sqrt{2}(2-1))=l\\4(\sqrt{2})=l\\Hence, l=b\\So, l-b= 0$