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Elis [28]
2 years ago
8

**POINTS**Find the values of X and y

Mathematics
1 answer:
Andrej [43]2 years ago
7 0

Answer:

y=105 for x

y=75

Step-by-step explanation:

2y-30=180                          180 (straight line)     180-105=75

+30      +30

2y=210

/2     /2

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Simplify the following expression.<br><br>10|3 - 7| + 24<br><br>​
weeeeeb [17]

Answer:

0

Step-by-step explanation:

The answer is 0 due to using PEMDAS

5 0
3 years ago
What is the inverse function for h(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-1" id="TexFormula1" title="\sqrt
Blizzard [7]

Step-by-step explanation:

y =  \sqrt{x + 7}  - 1

Replace x and y.

x =  \sqrt{y + 7}  - 1

Solve for y.

x + 1 =  \sqrt{y + 7}

Square both sides.

(x + 1) {}^{2}  = y + 7

(x + 1) {}^{2}  - 7 = y

This is the inverse function or you can also say

{x}^{2}  + 2x - 6 = y

5 0
2 years ago
ILL GIVE BRAINLEST Determine whether the two angles in each figure are complementary, supplementary, or neither
Firdavs [7]

Answer:

Step-by-step explanation:

If the sum of two angles = 180°

Then the pair of angles will be supplementary.

If the sum of two angles = 90°

Then the pair of angles will be complementary.

Sum of angles having measures 98° and 82° = 98° + 82°

                                                                          = 180°

Therefore, both the angles will be supplementary.

Sum of angles having measures 134° and 36° = 134° + 36°

                                                                            = 170°

Therefore, these angles are neither supplementary nor complementary.

So the answer is NEITHER.

8 0
3 years ago
Pls help as quick as possible 8th grade math!!!!!
Maksim231197 [3]

Answer:

1) y= 3x + 7

2) y= 3/4x + 10

3) y= -5x - 2

4) y= 12x - 6

5) y= 1/2 + 9

Step-by-step explanation:

6 0
2 years ago
PLEASE HELP WITH GRADE 11 MATH. Make sure you show the formula. Substitute values and show all mathematicall operations! show yo
Degger [83]

3x+y

x

​

 

=−3

=−y+3

​

The second equation is solved for xxx, so we can substitute the expression -y+3−y+3minus, y, plus, 3 in for xxx in the first equation:

\begin{aligned} 3\blueD{x}+y &= -3\\\\ 3(\blueD{-y+3})+y&=-3\\\\ -3y+9+y&=-3\\\\ -2y&=-12\\\\ y&=6 \end{aligned}

3x+y

3(−y+3)+y

−3y+9+y

−2y

y

​

 

=−3

=−3

=−3

=−12

=6

​

Plugging this value back into one of our original equations, say x = -y +3x=−y+3x, equals, minus, y, plus, 3, we solve for the other variable:

\begin{aligned} x &= -\blueD{y} +3\\\\ x&=-(\blueD{6})+3\\\\ x&=-3 \end{aligned}

x

x

x

​

 

=−y+3

=−(6)+3

=−3

​

The solution to the system of equations is x=-3x=−3x, equals, minus, 3, y=6y=6y, equals, 6.

We can check our work by plugging these numbers back into the original equations. Let's try 3x+y = -33x+y=−33, x, plus, y, equals, minus, 3.

\begin{aligned} 3x+y &= -3\\\\ 3(-3)+6&\stackrel ?=-3\\\\ -9+6&\stackrel ?=-3\\\\ -3&=-3 \end{aligned}

3x+y

3(−3)+6

−9+6

−3

​

 

=−3

=

?

−3

=

?

−3

=−3

​

Yes, our solution checks out.

Example 2

We're asked to solve this system of equations:

\begin{aligned} 7x+10y &= 36\\\\ -2x+y&=9 \end{aligned}

7x+10y

−2x+y

​

 

=36

=9

​

In order to use the substitution method, we'll need to solve for either xxx or yyy in one of the equations. Let's solve for yyy in the second equation:

\begin{aligned} -2x+y&=9 \\\\ y&=2x+9 \end{aligned}

−2x+y

y

​

 

=9

=2x+9

​

Now we can substitute the expression 2x+92x+92, x, plus, 9 in for yyy in the first equation of our system:

\begin{aligned} 7x+10\blueD{y} &= 36\\\\ 7x+10\blueD{(2x+9)}&=36\\\\ 7x+20x+90&=36\\\\ 27x+90&=36\\\\ 3x+10&=4\\\\ 3x&=-6\\\\ x&=-2 \end{aligned}

7x+10y

7x+10(2x+9)

7x+20x+90

27x+90

3x+10

3x

x

​

 

=36

=36

=36

=36

=4

=−6

=−2

​

Plugging this value back into one of our original equations, say y=2x+9y=2x+9y, equals, 2, x, plus, 9, we solve for the other variable:

\begin{aligned} y&=2\blueD{x}+9\\\\ y&=2\blueD{(-2)}+9\\\\ y&=-4+9 \\\\ y&=5 \end{aligned}

y

y

y

y

​

 

=2x+9

=2(−2)+9

=−4+9

=5

​

The solution to the system of equations is x=-2x=−2x, equals, minus, 2, y=5y=5y, equals, 5.

5 0
2 years ago
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