I think that this is a combination problem. From the given, the 8 students are taken 3 at a time. This can be solved through using the formula of combination which is C(n,r) = n!/(n-r)!r!. In this case, n is 8 while r is 3. Hence, upon substitution of the values, we have
C(8,3) = 8!/(8-3)!3!
C(8,3) = 56
There are 56 3-person teams that can be formed from the 8 students.
P=2l+2w
Since it is given that P=26m, length is 5 more than its width (w+5), we'll work it out in the perimeter formula.
26=2(w+5)+2w
26=2w+10+2w
26=4w+10
4w=26-10
4w=16
w=4
Thus the width is 4m. Let's find the length.
l=w+5
l=4+5
l=9
The length of a pen is 9m.
Answer:
Step-by-step explanation:
Write an equation to find the number of each type of ticket they should sell. Let "x" be # of adult tickets; Let "y" be # of student tickets: Value Equation: 5x+3y=450- b. Graph your equation.y = (-5/3)x+150
c. Use your graph to find two different combinations of tickets sold. I'll leave that to you.
LCM= 40
factors of 5- 5, 10, 15, 20, 25, 30, 35, 40*
factors of 8- 8, 16, 24, 32, 40*
Answer:
Answer choice C
Step-by-step explanation:
This is the only graph which has a linear equation and starts from 0,0.
