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3 years ago

Find the volume of a cone with a base radius of 6 yd and a height of 12 yd

Mathematics

1 answer:

anygoal [31]3 years ago

5 0

Answer:

452.38934 yd^3

Step-by-step explanation:

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Last year, the average math SAT score for students at one school was 475. The headmaster then introduced a new teaching method hoping to improve scores. This year, the mean math SAT score for a sample of students was 491. The headmaster concluded that the new teaching method produces higher SAT scores. The problem with reporting results this way is voluntary response. The information of how the teaching method isnot mentioned.

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3 years ago

Which expression is equivalent to (3-2^2) +5?

Arturiano [62]

The 3rd one is the right one!!!!!!!!!!!!!!!!!!

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3 years ago

30 treadmills to 36 elliptical machines the ratio in simplest form

Goshia [24]

30 treadmills : 36 ellipticals
this could be written in a few ways, but i am going to write it as a fraction. since treadmills come first, you put 30/36.

now that you have your fraction you have to find the GCF (greatest common factor) of the two numbers. the GCF is 6, so you have to divide 30 treadmills by 6, and 36 ellipticals by 6.
30/6=5
36/6=6

5/6 or 5:6 is the simplified ratio of treadmills to ellipticals

comment for any questions!!

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3 years ago

PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198

Elena-2011 [213]

The weight in 1980 is $\frac{4k}{5}$ kilograms

Solution:

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

To find: weight in 1980

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

The percentage increase is given by formula:

$\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100$

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

Substituting the values in formula,

$25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}$

Thus the weight in kilograms in 1980 is $\frac{4k}{5}$

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3 years ago

Screenshot down below math question

Volgvan

I believe the answer is 1.35 x10^14

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3 years ago