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Karolina [17]
2 years ago
12

What is the same as 15.39÷100

Mathematics
1 answer:
marysya [2.9K]2 years ago
7 0

1.539 divided by 10 which equal to 0.1539

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What is the answer to x+4=4x-17
Lesechka [4]

Answer:

x=7

Step-by-step explanation:

x+4=4x-17

4=3x-17

21=3x

x=7

5 0
3 years ago
Find the least common multiple (LCM) of 54 and 72. A) 9 B) 27 C) 108 D) 216
True [87]
The lowest common multiple is 216 (D)
4 0
3 years ago
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Which of the following is a solution of x2 + 2x + 4?
RideAnS [48]

Answer:

option-D

Step-by-step explanation:

we are given

x^2+2x+4

Let's assume it is equal to 0

x^2+2x+4=0

We can use quadratic formula

Suppose, we are given quadratic equations as

ax^2+bx+c=0

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

we can compare and find a,b and c

a=1 , b=2 , c=4

now, we can plug values

and we get

x=\frac{-2\pm \sqrt{2^2-4\cdot \:1\cdot \:4}}{2\cdot \:1}

now, we can simplify it

and we get

x=-1+\sqrt{3}i,\:x=-1-\sqrt{3}i


6 0
3 years ago
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Use the model to solve for x.<br> A) x = -5 <br> B) x = 5/4<br> C) x = 5/3<br> D) x = -5/4
STatiana [176]

i think this answer would be C that would be my choice :)

8 0
3 years ago
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if a snowball rolls down a hill and its surface area increaces at a rate of 18cm^2/min, find the rate at which the radius increa
sp2606 [1]

Answer: dr/dt = 9/(24pi)  cm per minute

9/(24pi) is approximately equal to 0.119366

=============================================

Work Shown:

Given info

dS/dt = 18 cm^2/min is the rate of change of the surface area

r = 6 cm is the radius, from the fact that the diameter is 12 cm

--------

Use the surface area equation given, apply the derivative, plug in the given values and then isolate dr/dt which represents the rate of change for the radius

S = 4*pi*r^2

dS/dt = 2*4*pi*r*dr/dt

dS/dt = 8*pi*r*dr/dt

18 = 8*pi*6*dr/dt

18 = 48*pi*dr/dt

48pi*dr/dt = 18

dr/dt = 18/(48pi)

dr/dt = (9*2)/(24*2pi)

dr/dt = 9/(24pi)

The units are cm per minute, which can be written as cm/min.

3 0
3 years ago
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