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Karolina [17]
2 years ago
12

What is the same as 15.39÷100

Mathematics
1 answer:
marysya [2.9K]2 years ago
7 0

1.539 divided by 10 which equal to 0.1539

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What value of x makes the equation true?
NNADVOKAT [17]

x= -4 because 1.4 times -4=- 5.6 and 2.6 times -4=-10.4 and when we add to numbers postive or negative numbers it stays positive or negative depnding on the problem and 10.4 + 5.6 + 16 however becuase both were negative the answers stays negative making the answer _ 16 and it says 1.4x+2.6x=-16 so the correct answer is x= -4

5 0
3 years ago
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How do you simplify this
kramer

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multiply the bottom and the top by route 2 minus route 3

this gives 4 route 2 minus route 18 over minus 1

this gives minus 4 route 2 add route 18

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3 0
3 years ago
-3(-4r - 5)<br> combining like terms
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r

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Step-by-step explanation:

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A small town has 2000 families. The average number of children per family is mu = 2.5, with a standard deviation sigma = 1.7. A
Nikitich [7]

Answer:

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable that represent the number of children per fammili of a population, and for this case we know the following info:

Where \mu=2.5 and \sigma=1.7

We select a sample of n =64 >30 and we can apply the central limit theorem. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And for this case the standard error would be:

\sigma_{\bar X} = \frac{1.7}{\sqrt{64}}= 0.2125

6 0
3 years ago
Tamara is bringing refreshments to a
andrew-mc [135]
She should buy 5 liters of juice.
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3 years ago
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