Sal has already finished 5/9 of the 45 math problems he was assigned. If each math problem took him 3/5 of a minute to finish an
d this pace continues, which expression can be used to determine the amount of time it will take him to finish his remaining homework?
45 times 5/9 times 3/5
45 times 5/9 divided by 3/5
45 times 4/9 times 3/5
45 times 4/9 divided by 3/5
please answer fast its timed
45 times 5/9 times 3/5
45 times 5/9 divided by 3/5
45 times 4/9 times 3/5
45 times 4/9 divided by 3/5
please answer fast its timed
1 answer:
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I'll do Problem 8 to get you started
a = 4 and c = 7 are the two given sides
Use these values in the pythagorean theorem to find side b
With respect to reference angle A, we have:
- opposite side = a = 4
- adjacent side = b =
- hypotenuse = c = 7
Now let's compute the 6 trig ratios for the angle A.
We'll start with the sine ratio which is opposite over hypotenuse.
Then cosine which is adjacent over hypotenuse
Tangent is the ratio of opposite over adjacent
Rationalizing the denominator may be optional, so I would ask your teacher for clarification.
So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.
- cosecant, abbreviated as csc, is the reciprocal of sine
- secant, abbreviated as sec, is the reciprocal of cosine
- cotangent, abbreviated as cot, is the reciprocal of tangent
So we'll flip the fraction of each like so:
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Summary:
The missing side is
The 6 trig functions have these results
Rationalizing the denominator may be optional, but I would ask your teacher to be sure.