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marysya [2.9K]
3 years ago
11

Simplify. 3x−6 Assume no denominator equals zero.

Mathematics
1 answer:
LekaFEV [45]3 years ago
8 0

Step-by-step explanation:

3x-6 =0

3x= 6-0

3x =6

x=6/3

x=2

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A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect
Vladimir79 [104]

The probability that the first two electric toothbrushes sold are defective is 0.016.

The probability of an event, say E occurring is:

P(E)=\frac{n(E)}{N}

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = the number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is n = 20.

The number of defective electric toothbrushes is x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

(\left {{20} \atop {2}} \right. )=\frac{20!}{2!(20-2)!} =\frac{20!}{2!18!} =\frac{20*19*18!}{2!*18!} = 190

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

(\left {{3} \atop {2}} \right. )=\frac{3!}{2!(3-2)!} =\frac{3!}{2!1!} =\frac{3*2!}{1!2!} =3

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

\frac{3}{190}\\ =0.01579\\=0.016

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

Learn more about probability here brainly.com/question/27474070

#SPJ4

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