Answer:
81 times the original size.
Step-by-step explanation:
AA0ktA=3A0=?=?=25hours=A0ekt
Substitute the values in the formula.
3A0=A0ek⋅25
Solve for k. Divide each side by A0.
3A0A0=e25k
Take the natural log of each side.
ln3=lne25k
Use the power property.
ln3=25klne
Simplify.
ln3=25k
Divide each side by 25.
ln325=k
Approximate the answer.
k≈0.044
We use this rate of growth to predict the number of bacteria there will be in 100 hours.
AA0ktA=3A0=?=ln325=100hours=A0ekt
Substitute in the values.
A=A0eln325⋅100
Evaluate.
A=81A0
At this rate of growth, we can expect the population to be 81 times as large as the original population.
It depends on the sequence type.
if it's a regular sequence with a first common difference, you can use the formula a+d(n-1). here, "a" is the first term, "d" is the common difference and "n" is the term number.
Y 6 8 10 12 X - because it increases at a constant rate of 2
Parallel lines have same slope, so first isolate y to get the equation into y=mx+b form.
-2x+3y=2
3y = 2x + 2
Now plug the point (3,4) into y = 2x + b
4 = 2(3) + b
Solves for be
b = -2
So the new equation is y = 2x - 2
