For this case, the first thing you should know is:
d: v * t
Where,
d: distance
v: speed
t: time
To go to school by bus we have:
d = 45 * t
To return from school we have:
d = 2.5 * (1-t)
how the distance is the same:45 * t = 2.5 * (1-t)
Answer:
the equation that will help find the time it takes chelsea to get to school on the bus is:
45 * t = 2.5 * (1-t)
Note: the equation will have one solution.
Step-by-step explanation:
definition of the derivative to differentiate functions. This tutorial is well understood if used with the difference quotient .
The derivative f ' of function f is defined ascthe above pic.
when this limit exists. Hence, to find the derivative from its definition, we need to find the limit of the difference quotient.
You did south, north, correctly
but last one
twice north is 2 times (x+48) or 2x+96
so
s=x
n=x+48
c=4x
s+c>2x+96
subsitute s for x and 4x for c
x+4x>2x+96
5x>2x+96
minus 2x both sides
3x>96
divide both sides by 3
x>32
it cannot be equal to 32 so
the minimum value is 33 spaces in south car park
Answer:
15 kilometres
Step-by-step explanation:
Based on the wording of your question, I am assuming you already know that Paul ran 250 metres every 1 minute, and that the ratio is 250:1. To get the second part of the answer, convert metres to kilometres. 0.001*250= 0.25. Paul ran 0.25 kilometres per minute. The ratio of kilometres per minute is 0.25:1. Next, convert minutes to hours. Multiply the entire ratio by 60, as there are 60 minutes in an hour. The ratio of kilometeres per minute is 15:60, and the ratio of kilometres per hour is 15:1, meaning Paul ran 15 kilometres in one hour.
Answer:
(2x+3y)(x2+3x+2). it may helps you
