Question

When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

Answer 1

Answer:

14

Step-by-step explanation:

${3x}^{2} - 2y \\ 3 { \times 3}^{2} - 2 \times 5 \\ 27 - 10 = 17$

${2x}^{2} - 3y \\ 2 \times {3}^{2} - 3 \times 5 \\ 12 - 15 = - 3$

$17 - 3 = 14$

Answer 2

11 I’m pretty sure. Since 3x times 2 is 18 - 2y which is 10. The first thing is 10. And since 2x times two is 12, if you subtract that by 3y which is 15 you would get -3. The difference of 10 and -3 you get 13.