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3 years ago

14

Help this is do in 5 minutes

2 answers:

IrinaVladis [17]3 years ago

6 0

Step-by-step explanation:

<1 and <2 are adjacent, Supplementary and linear pair angles

wariber [46]3 years ago

3 0

They are adjacent and supplementary

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A bag contains 5 red marbles, 10 blue marbles, and 14 yellow marbles. If Jen selects a marble from the bag without looking, what

Darina [25.2K]

Answer:

The answer to your question is 0.83 or 83%

Step-by-step explanation:

Data

5 red marbles

10 blue marbles

14 yellow marbles

Process

1.- Calculate the total amount of marbles

Total amount = 5 red + 10 blue + 14 yellow

Total amount = 29 marbles

2.- Calculate the amount of marbles that are not red

No red marbles = 10 + 14

= 24 marbles

3.- Calculate the probability

Probability of not pulling a red marble = $\frac{no red marble}{total amount of marbles}$

Probability of not pulling a red marble = $\frac{24}{29} = 0.83 or 83%$

5 0

3 years ago

Phoebe compared the cost of books in 9 different stores.

krek1111 [17]

You have to put the numbers in order and find the middle value so in this case it's-

2, 4, 4, 5, 6, 7, 8, 8, 8

The answer is $6

7 0

3 years ago

Find the product.<br><br> (8-3z)(8+3z)

maks197457 [2]

Step-by-step explanation:

you can open the file I gave you now. the answer is there

7 0

3 years ago

You have $5,000 to invest for ten years. The Bank pays simple interest at an annual rate of 5%. Calculate your balance after 10

Mazyrski [523]

Answer: $7,500

Step-by-step explanation:

Use the formula: SI = P(1 + rt)

SI = 5000(1 + 0.05[10])

SI = 5000 + 2500

SI = $7,500

After 10 years, your balance should be $7,500

3 0

2 years ago

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )

Gemiola [76]

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:$ or $x-4\:>\:8$

$x\:$ or $x\:>\:8+4$

$x\:$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -\frac{10}{3}$ and $x\leq 2$

$-\frac{10}{3}\leq x\leq2$

We write this in interval form to get,

$[-\frac{10}{3},2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:$ or $1-5a\:>\:29$

This implies that,

$-5a\:$ or $-5a\:>\:29-1$

$-5a\:$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:$

We write this in interval notation to get,

$(-\infty,-\frac{28}{5})\cup (6,+\infty)$

7 0

3 years ago