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podryga [215]
3 years ago
5

What is 8 thousands 15 hundreds 15 Tens 18 ones written in standard form ?

Mathematics
2 answers:
ryzh [129]3 years ago
8 0
I'm not sure what you are trying to convey, but you cannot have more than one digit, so this is imposible
Mariulka [41]3 years ago
7 0
8 x 1000 + 15 x 100 + 15 x 10 + 18 x 1
= 8000 + 1500 + 150 + 18
= 9500 + 168
= 9668
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Find the area of the shaded region. Show your work please
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So if the formula is A=(pi)r^2, find the area of the entire circle:
A=(pi)(13^2)=530.66cm
then find the area of the little circle:
A=(pi)(3^2)= 28.26cm
then subtract the little circle from the big circle:
530.66cm-28.26cm= 502.4cm
and there you go. Hope this helps!

4 0
3 years ago
I need the answer quick before my timer goes out
max2010maxim [7]

Answer:

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Step-by-step explanation:

4 0
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Solve the inequality x/5-3<0
Kisachek [45]

Answer:

x < 15

Step-by-step explanation:

\frac{x}{5} - 3 < 0 ( add 3 to both sides )

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7 0
3 years ago
Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle
balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0
3 years ago
Indicate the equation of the given line in standard form. The line through the midpoint of and perpendicular to the segment join
lianna [129]
The midpoint is (3,-1) 

5 0
3 years ago
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