What is the solution of equations graphed below?A. (2,4)B. (4,2)C. (0,6)D. (6,0)

Mathematics

2 answers:

Ksenya-84 [330]3 years ago

7 0

Answer & Step-by-step explanation:

To find the solution of equations graphed on a line, the solution is going to be the point where the two lines meet or cross.

So, in the diagram, we can see that the equations do cross at a certain point. This point is (4,2).

So, the solution of the equations graphed is (4,2)

vivado [14]3 years ago

3 0

Answer:

(4,2)

Step-by-step explanation:

The solution to the system is where the two graphs overlap

The two graphs cross at x=4 y =2

(4,2)

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The measure (in inches) of the sides of triangle RIO are equivalent to three consecutive odd integers. The perimeter is 201 inch

mariarad [96]

Let
x-------------> first odd integer
x+2---------> second odd integer
x+4---------> third odd integer

we know that
(x)+(x+2)+(x+4)=201--------> 3x+6=201--------> 3x=195-------> x=65

the three sides of triangle RIO are
x=65 in
x+2-----> 65+2-----> 67 in
x+4----> 65+4------> 69 in

then
69²=4761----------> c²
(65²+67²)=8714--------> a²+b²
c² < (a²+b²)---------> the triangle RIO is not obtuse
Is acute angle triangle

statements
1) The triangle is obtuse--------> is false
Is acute angle triangle

2) The triangle is scalene-----> is correct
The three sides measures are diferent

3)The smallest side measures 61 inches--------> is false
The smallest side measures 65 in

4)The largest side measures 69 inches-------> is correct

5) If triangle RIO is dilated of 1/3, then the perimeter of the dilated triangle will be 3 units smaller
If triangle RIO is dilated of 1/3, then news sides are
65/3------> 21.67 in
67/3-------> 22.33 in
69/3------> 23 in

the new perimeter is=21.67+22.33+23------> 67 in
201-67=134 in
therefore
If triangle RIO is dilated of 1/3, then the perimeter of the dilated triangle will be 3 units smaller----------> is false

Because the perimeter of the dilated triangle will be 134 units smaller

6 0

3 years ago

Read 2 more answers

Find all the zeros of the equation x^4-6x^2-7x-6=0

rusak2 [61]

Answer:

The zeros are

$x=-2,\:x=3,\:x=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$

Step-by-step explanation:

We have been given the equation x^4-6x^2-7x-6=0

Use rational root theorem, we have

$a_0=6,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:2,\:3,\:6,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:2,\:3,\:6}{1}$

$-\frac{2}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+2$

$=\left(x+2\right)\frac{x^4-6x^2-7x-6}{x+2}\\$

$=x^3-2x^2-2x-3$

Again factor using the rational root test, we get

$=\left(x+2\right)\left(x-3\right)\left(x^2+x+1\right)$

Using the zero product rule, we have

$x+2=0:\quad x=-2\\x-3=0:\quad x=3\\x^2+x+1=0\\\\x_{1,\:2}=\frac{-1\pm \sqrt{1^2-4\cdot \:1\cdot \:1}}{2\cdot \:1}\\\\=-\frac{1}{2}+i\frac{\sqrt{3}}{2},\:x=-\frac{1}{2}-i\frac{\sqrt{3}}{2}$