What is the solution of equations graphed below?A. (2,4)B. (4,2)C. (0,6)D. (6,0)

2 answers:

7 0

Answer & Step-by-step explanation:

To find the solution of equations graphed on a line, the solution is going to be the point where the two lines meet or cross.

So, in the diagram, we can see that the equations do cross at a certain point. This point is (4,2).

So, the solution of the equations graphed is (4,2)

3 0

Answer:

(4,2)

Step-by-step explanation:

The solution to the system is where the two graphs overlap

The two graphs cross at x=4 y =2

(4,2)

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Answer:

See Explanation.

General Formulas and Concepts:

Pre-Algebra

Algebra II

Calculus

Derivatives

Basic Power Rule:

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Derivative of Ln: $\frac{d}{dx} [ln(u)] = \frac{u'}{u}$

Step-by-step explanation:

Step 1: Define

$ln(\frac{2x-1}{x-1} )=t$

Step 2: Differentiate

Rewrite: $t = ln(\frac{2x-1}{x-1})$
Rewrite [Ln Properties]: $t = ln(2x-1) - ln(x - 1)$
Differentiate [Ln/Chain Rule/Basic Power Rule]: $\frac{dt}{dx} = \frac{1}{2x-1} \cdot 2 - \frac{1}{x-1} \cdot 1$
Simplify: $\frac{dt}{dx} = \frac{2}{2x-1} - \frac{1}{x-1}$
Rewrite: $\frac{dt}{dx} = \frac{2(x-1)}{(2x-1)(x-1)} - \frac{2x-1}{(2x-1)(x-1)}$
Combine: $\frac{dt}{dx} = \frac{-1}{(2x-1)(x-1)}$
Reciprocate: $\frac{dx}{dt} = -(2x-1)(x-1)$
Distribute: $\frac{dx}{dt} = (1-2x)(x-1)$