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mafiozo [28]
3 years ago
13

Can anyone PLEASE help me with this math problem pls?

Mathematics
1 answer:
Delvig [45]3 years ago
8 0

Answer:

b) 1/4n^2

Step-by-step explanation:

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The following table gives three different relations.
Drupady [299]

Answer:

First relation: It's a function. No order pair need to be changed.

Second relation: It's a function. No order pair need to be changed.

Third relation: It's not a function. The ordered pair (5,8) needs to be changed.

Step-by-step explanation:

A function may not have two y-values assigned to the same x-value.

Each x-element of the first relation has only one y-element associated with it. So we conclude that it's a function.

Each x-element of the second relation has only one y-element associated with it. So we conclude that it's a function.

The points (5,8) and (5,2) shows that there are two y-elements (y=8 and y=2) associated with the value x=5. So we conclude that it's not a function.

8 0
4 years ago
5x - y = 6<br> -2x +y = 8<br> What’s the answer
nevsk [136]

Answer:

x= 4\frac{2}{3}

y= 17\frac{1}{3}

Step-by-step explanation:

5x-y=6\\-2x+y=8\\

Simplify, find the x-value first:

3x=14\\x=4\frac{2}{3}

Substitute x-value into any equation (i did the second equation) and simplify:

-2(4\frac{2}{3})+y=8\\ -9\frac{1}{3} +y=8\\

y=17\frac{1}{3}

4 0
4 years ago
PLEASE HELP!!! Find out what is the gamma angle γ in the a obtuse triangle below. Use the tangent concept to help.
ra1l [238]

Answer:

sorry I don't understand just trying to get points

7 0
3 years ago
Read 2 more answers
The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the
Temka [501]
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
7 0
3 years ago
Math Can you Help me out? Giving Brainliest, can you also explain your answer
AleksAgata [21]

Answer:

Only 5

Step-by-step explanation:

You just place each in. The one that fits in the equation is the right one.

11-5=6 and 6 is less than 7.

11-3=8 and 8 is greater so it doesn't work.

8 0
3 years ago
Read 2 more answers
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