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g100num [7]
2 years ago
7

The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the

table below.

Mathematics
1 answer:
Temka [501]2 years ago
7 0
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
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Answer:

y = \frac{32}{3}

Step-by-step explanation:

Firstly, move over the negative 3/4 fraction (don't forget to swap the operation i.e subtract to add):

\frac{y}{8} = \frac{7}{12}  + \frac{3}{4}

Now, to add the two fractions, simply multiply the numerator and denominator by 3:

\frac{3*3}{4*3} = \frac{9}{12}

Now add this to the other fraction:

\frac{9}{12} + \frac{7}{12} = \frac{16}{12}

This can be simplified down by dividing both the numerator and denominator by 4:

\frac{4}{3}

Which now simplifies the original equation to:

\frac{y}{8}  = \frac{4}{3}

Remove the y out of the fraction:

\frac{1}{8}y = \frac{4}{3}

Now multiply both sides by 8:

(\frac{1}{8}y) * 8 = (\frac{4}{3}) * 8

y = \frac{4*8}{3}

y = \frac{32}{3}

Hope this helps!

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