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Irina18 [472]
3 years ago
14

Please help me! :( I will give brainliest

Physics
1 answer:
-BARSIC- [3]3 years ago
8 0
It’s 8 babe good luck
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A 0.144kg baseball is pitched horizontally at 38.0 m/s. After the baseball is hit by the bat, it moves at the same speed, but in
Hoochie [10]

Answer:

Given:

mass of the ball m = 0.144 kg

velocity v = 38 m/s

now,  change in momentum

P = m v- ( - mv)

  = 2 mv

  =2 x (0.144) x (38)

  = 10.944 kg-m/s

Impulse J= F. Δt

change in momentum is equal to impulse

J = 10.944 kg-m/s

we know force is equal to change in momentum per unit time

F = \dfrac{P}{t}

F = \dfrac{10.944}{0.8\times 10^{-3}}

F = 13.68 x 10³ N

F = 13.68 kN

3 0
4 years ago
The label on a bottle of soda can shows the can contains 397 ml of soda how many litters of soda are in one can
Basile [38]

Answer:

A

Explanation:

1000ml = 1l

397ml = 0.397l

8 0
3 years ago
A block with mass m =6.4 kg is hung from a vertical spring. When the mass hangs in equilibrium, the spring stretches x = 0.28 m.
Zanzabum

Answer

given,

mass of block (m)= 6.4 Kg

spring is stretched to distance, x = 0.28 m

initial velocity = 5.1 m/s

a) computing weight of spring

    k x = m g

k = \dfrac{mg}{x}

k = \dfrac{6.4 \times 9.8}{0.28}

      k = 224 N/m

b) f = \dfrac{\omega}{2\pi}

    \omega = \sqrt{\dfrac{k}{m}}= \sqrt{\dfrac{224}{6.4}} = 5.92 \ rad/s

   f = \dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}

   f = \dfrac{1}{2\pi}\sqrt{\dfrac{224}{6.4}}

  f =0.94\ Hz

c)  v_b = -v cos \omega t

    v_b = -5.1 \times cos (5.92 \times 0.42)

    v_b = 4.04\ m/s

d)  a_{max} = v \omega

    a_{max} = 4.04 \times 5.92

    a_{max} =23.94\ m/s^2

e)  Y =- A sin (\omega t)

    A = \dfrac{v}{\omega}

    A = \dfrac{4.04}{5.92}

        A = 0.682 m

    Y =- 0.682 \times sin (5.92 \times 0.42)

    Y =- 0.42

Force =m \omega^2 |Y|

          =6.4 \times 5.92^2\times 0.42

F = 94.20 N

4 0
4 years ago
A mass (m = 30 g) falls onto a spring (k = 7.3 N/m) from a height (h = 25 cm). The spring compresses an additional amount x befo
yulyashka [42]

Answer:

x₁ = 0.1878 m

Explanation:

For this exercise we will use conservation of energy

starting point. Highest point

         Em₀ = U = m g h

final point. Lowest point with fully compressed spring

         Em_f = K_e + U

         Em_f = ½ K x² + m g x

         

energy is conserved

         Em₀ = Em_f

        m g h = ½ K x² + m g x

       ½ K x² + mg (x- h) = 0

         

let's substitute

       ½ 7.3 x² + 0.030 9.8 (x- 0.25) = 0

        3.65 x² + 0.294 (x- 0.25) = 0

        x² + 0.080548 (x- 0.25) = 0

        x² - 0.020137 + 0.080548 x = 0

        x² + 0.080548 x - 0.020137 = 0

let's solve the quadratic equation

      x = [0.080548 ±√ (0.080548² + 4   0.020137)] / 2

      x = [0.080548 ± 0.29502] / 2

      x₁ = 0.1878 m

      x₂ = -0.1072 m

These are the compression and extension displacement of the spring

4 0
3 years ago
Trace the path of energy from the sun to mechanical energy in an organism
densk [106]
Sun to plants. Plants use photosynthesis to create sugar for energy. Animals then eat the plant and the energy they made is absorbed by the animal.
5 0
3 years ago
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