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yan [13]
1 year ago
5

how much work did the movers do (horizontally) pushing a 41.0- kg crate 10.3 m across a rough floor without acceleration, if the

effective coefficient of friction was 0.60?
Physics
1 answer:
11111nata11111 [884]1 year ago
7 0

W=2485.65 J ,work did the movers do friction force a 41.0- kg crate 10.3 m across a rough floor without acceleration

<h3>What is a basic friction force?</h3>

Two surfaces that come into contact and slide against one another produce a force known as frictional force. Several aspects that influence the frictional force include: The surface texture as well as the amount of force attracting them together have the most effects on these forces.

<h3>What outcomes does friction produce?</h3>

It generates heat, which is useful for warming our bodies or specific areas of any object. Power is also lost as a result. It makes noise during every operation. We are able to walk, run, dance, etc. due to friction.

To know  more about friction force visit:

brainly.com/question/1389727

#SPJ4

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Need help in Psychology. Please help! Which of the following statements best describes abductive reasoning? A.I think,therefore
Pepsi [2]
The "D) People perceive objects as a whole" statement best describes an abductive reasoning. The abductive reasoning often has incomplete information as the base of its reasoning and the conclusion for this type of reasoning is not absolute. There will always be additional pieces of evidence and factors that could change the conclusion of this reasoning. Therefore<span> D statement is the most suitable answer.</span>
5 0
3 years ago
what is the focalength of the combination of two thin renses of power -5D and -2D placeci in contact with each other?​
Ghella [55]

Answer:

f = - 0.143 m = - 14.3 cm

Explanation:

First, we will calculate the power of the combination of lenses:

P = P₁ + P₂

where,

P = Power of Combination = ?

P₁ = Power of first lens = - 5D

P₂ = Power of second lens = - 2D

Therefore,

P = - 5D - 2D

P = - 7D

Now, the focal length can be given as:

f = \frac{1}{P} \\\\f = \frac{1}{-\ 7\ D} \\\\

<u>f = - 0.143 m = - 14.3 cm</u>

Negative focal length indicates that combination will act as diverging lens.

6 0
3 years ago
A dipole is located at the origin, with charges +3 nC and -3 nCseparated by 4 μm. Consider a spherical Gaussian surfacecentered
kirza4 [7]

Answer:

Explanation:

a )  

The Gaussian surface must  have contained both the charges like +3 nC and - 3 nC , total charges being zero . According the Gauss's law , total electric flux over a closed surface is equal to 1 / ε₀ times the total charge contained inside the closed surface .

Since total charge inside is zero , total flux will be 1 /  ε₀ x 0 = 0

b )

In this case the Gaussian surface is so small that it contains only the charge

+ 3 nC .

So electric flux over the Gaussian surface

= (  1 /  ε₀ ) x 3 x 10⁻⁹

= (1 / 8.85 x 10⁻¹² ) x 3 x 10⁻⁹

= 3 x 10³ / 8.85

= 339 weber.  

=

6 0
3 years ago
Where must an object be placed to form an image 30.0 cm from a diverging lens with a focal length of 43.0 cm?
Schach [20]
Using lens equation;

1/o + 1/i = 1/f; where o = Object distance, i = image distance (normally negative), f = focal length (normally negative)

Substituting;

1/o + 1/-30 = 1/-43 => 1/o = -1/43 + 1/30 = 0.01 => o = 1/0.01 = 99.23 cm

Therefore, the object should be place 99.23 cm from the lens.
6 0
3 years ago
A transverse, travelling wave on a chord is represented by = 0.22sin (5.6 + 34) where and are in meters and is in seconds. For t
Neko [114]

Answer:

A)  1.122 m

B)  5.4 hertz

C)  6.06 m/s ( towards negative  x axis )

D)  0.22

E)  max speed = amplitude * 34

                  = 0.22 * 34 = 7.48

  minimum speed ( speed at rest ) = 0

Explanation:

The travelling wave = D = 0.22sin ( 5.6x + 34t)

this wave is represented in the form : D = Asin ( kx + wt)

A) wavelength

k = 2\pi / v

v = wavelength

k = 5.6

therefore wavelength ( v ) from the equation = 2\pi / 5.6 = 1.122 m

B ) frequency

w = 2\pif

w = 34

f = frequency

therefore f = w / 2\pi  = 34 / 2\pi = 5.4 hertz

C ) velocity

speed = f v

v = 5.4 * 1.122 = 6.06 m/s ( towards negative  x axis )

D) amplitude

A = 0.22

E ) maximum and minimum speeds of particles on the chord

max speed = amplitude * 34

                  = 0.22 * 34 = 7.48

minimum speed ( speed at rest ) = 0

5 0
3 years ago
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