What is the slope of a line thatpasses through the points (2,3) and (5,20)

During which section did the person travel the farthest? how far did they travel ?

Crank

Answer:

a

Step-by-step explanation:

i think it is (a)

4 0

3 years ago

Use the substitution method to solve this system of equations.

KATRIN_1 [288]

Answer:

Point Form- (5,1) Equation Form- x=5, y=1

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Directions: Use slope to determine if lines PQ and RS are parallel, perpendicular, or neither. 13. P(-9, -4), (-7, -1), R(-2,5),

Rudik [331]

Answer:

Parallel

Step-by-step explanation:

Given points

P(-9, -4), Q(-7, -1), R(-2,5), S(-6, -1)

Finding slopes of PQ and RS using slope formula

m = (y2 - y1)/(x2 - x1)

Slope of line PQ

m = (-1 - (-4))/(-7 - (-9)) = 3/2

Slope of line RS

m = (-1 - 5)/(-6 - (-2)) = -6 / -4 = 3/2

Slopes are same, therefore lines are parallel

7 0

3 years ago

A store manager times janette to see how long it would take her to fold and put away a sweater , a shirt , a pair of pants and a

Nataly [62]

$\frac{26.1+24.3+33.8+18.2}{4}= \frac{128}{4}=25.6$

Your answer is 25.6 seconds in average.

4 0

3 years ago

A survey was conducted at two colleges. 500 students at College A participated in the study. The results indicated that on avera

bagirrra123 [75]

Answer:

$t=\frac{(15-20)-0}{\sqrt{\frac{5^2}{500}+\frac{4^2}{400}}}}=-16.67$

The p value would be given by:

$p_v =2*P(t_{898}$

Since the p value is a very low value we have enough evidence to reject the null hypothesis and we can conclude that we have significant difference in the means of time spent for online assignments between the two colleges

Step-by-step explanation:

Data given

$\bar X_{1}=15$ represent the mean for sample A

$\bar X_{2}=20$ represent the mean for sample B

$s_{1}=5$ represent the sample standard deviation for A

$s_{f}=4$ represent the sample standard deviation for B

$n_{1}=500$ sample size for the group A

$n_{2}=400$ sample size for the group B

$\alpha=0.01$ Significance level provided

t would represent the statistic

System of hypothesis

The system of hypothesis is the true difference in the time students spent for online assignments between the two colleges, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

Since we don't know the deviations the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

The degrees of freedom are given by $df=n_1 +n_2 -2=500+400-2=898$

Replacing the info given we got:

$t=\frac{(15-20)-0}{\sqrt{\frac{5^2}{500}+\frac{4^2}{400}}}}=-16.67$

The p value would be given by:

$p_v =2*P(t_{898}$

Since the p value is a very low value we have enough evidence to reject the null hypothesis and we can conclude that we have significant difference in the means of time spent for online assignments between the two colleges

3 0

3 years ago