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yan [13]
3 years ago
11

Use a table of values to find the solution to the equation f(x)=h(x) where

Mathematics
1 answer:
GuDViN [60]3 years ago
6 0

9514 1404 393

Answer:

  x = 2 1/3

Step-by-step explanation:

We can examine the equations to see where the solution lies.

<u>f(x) = (2/3) -x</u>

This has an x-intercept where y=0, at x=2/3. It has a y-intercept where x=0, at y=2/3. Its slope is -1.

<u>h(x) = 3 -2x</u>

This has an x-intercept where y=0, at x=3/2. It has a y-intercept where x=0, at y=3. Its slope is -2.

__

In the first quadrant, the graph of h(x) is farther from the origin and steeper than the graph of f(x). The lines must cross in the 4th quadrant at some value of x that is greater than 3/2. The fraction in the definition of f(x) suggests that the solution will be a multiple of 1/3.

The attached table shows a couple of guesses at values of x that would make f(x) = h(x). We find that x = 7/3 is the solution we're looking for.

_____

<em>Additional comment</em>

Repetitive function evaluations are done conveniently and with fewer errors by a calculator or spreadsheet that can work with tables of values. Here, we have used a graphing calculator. These tools are readily available for free on almost any phone, tablet, or desktop computer platform.

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F(x) = x^2 + 3 g(x) = 4x - 3 Find (f°g)(-1)​<br><br>a. 4<br>b. -52<br>c. -4<br>d. 52
Yanka [14]

Answer:

Step-by-step explanation:

g(-1) = 4(-1) - 3 = -4 -3 = -7

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Answer is D

4 0
4 years ago
Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b
poizon [28]

The roots of the given polynomials exist  $x=8+\sqrt{10}$, and $x=8-\sqrt{10}$.

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\

$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\

$&x=8+\sqrt{10}, x=8-\sqrt{10}

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$, and

$x=8-\sqrt{10}$.

To learn more about quadratic equations refer to:

brainly.com/question/1214333

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3 0
2 years ago
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notsponge [240]

Number 6

Answer:

y = (c - ax)/b

Step-by-step explanation:

ax + by = c

by = c - ax

y = (c - ax)/b

<em>I answered number 5 in your last question.</em>

3 0
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Which of the following best describes the algebraic expression 7(x+12)-4 ?
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Vesna [10]

Answer:

B)   x = 8\sqrt{3} ;  y = 4\sqrt{3}

Step-by-step explanation:

in a 30-60-90° triangle the sides, respectively, are in the ratio of

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we can find 'x' by creating this proportion:

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cross-multiply to get:

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we can simplify this by 'rationalizing the denominator' which is to

multiply numerator and denominator by \sqrt{3} to get:

(24\sqrt{3})÷3, which is 8\sqrt{3}

we know that side 'y' is half that of side 'x'

therefore y = 4\sqrt{3}

3 0
3 years ago
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