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Masteriza [31]
4 years ago
10

F(x) = x^2 + 3 g(x) = 4x - 3 Find (f°g)(-1)​a. 4b. -52c. -4d. 52

Mathematics
1 answer:
Yanka [14]4 years ago
4 0

Answer:

Step-by-step explanation:

g(-1) = 4(-1) - 3 = -4 -3 = -7

f(-7) = (-7)^2 + 3 = 49 + 3 = 52

Answer is D

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Joseph's front porch is rectangular. The length is 8 feet more than the width. The
KonstantinChe [14]
It Hass to be definitely B because there’s no other way it’s leading up to a C or D so I’m gonna stick with my answer
5 0
3 years ago
Which of the following lines are parallel to 2Y - 3X = 4?
dimulka [17.4K]

Answer:

B. Y = 6/4 X

Step-by-step explanation:

Well to find its parallel line we need to put,

2y - 3x = 4 into slope-intercept.

+3x to both sides

2y = 3x + 4

Now we divide everything by 2,

y = 3/2x + 2

So a line that is parallel to the given line will have the same slope but different y intercept, meaning we can cross out choices A and C.

To check look at the image below ↓

<em>Thus,</em>

<em>answer choice B. Y = 6/4 X is correct.</em>

<em />

<em>Hope this helps :)</em>

4 0
3 years ago
At a certain coffee shop, all the customers buy a cup of coffee and some also buy a doughnut. The shop owner believes that the n
wolverine [178]

Answer:

(1) The probability that the shop owner sells over 2000 cups of coffee in a week is 0.2514.

(2) The shop owner has no reasonable chance to expect earning a profit more than $300.

(3) The probability that the shop owner will sell a doughnut to more than half of his coffee customers is 0.2611.

Step-by-step explanation:

Let <em>X</em> = number of cups of coffee sold and <em>Y</em> = number of donuts sold.

The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = 320 and <em>σ </em>= 20.

The random variable <em>Y</em> follows a Normal distribution with parameters <em>μ</em> = 150 and <em>σ </em>= 12.

The shop owner opens the shop 6 days a week.

(1)

Compute the probability that the shop owner sells over 2000 cups of coffee in a week as follows:

P(X>2000)=P(\frac{X-\mu}{\sigma}>\frac{2000-(6\times320)}{6\times20})\\=P(Z>0.67)\\=1-P(Z

Thus, the probability that the shop owner sells over 2000 cups of coffee in a week is 0.2514.

(2)

The equation representing the profit earned on selling 1 cup of coffee and 1 doughnut in a day is:

P = 0.5<em>X</em> + 0.4<em>Y</em>

Compute the probability that the shop owner earns more than $300 as profit as follows:

P(Profit>300)=P(\frac{Profit-\mu}{\sigma}>\frac{300-((0.5\times320)+(0.4\times150))}{\sqrt{0.5^{2}(20)^{2}+0.4^{2}(12)^{2}}})\\=P(Z>7.21)\\\approx0

The probability of earning a profit more then $300 is approximately 0.

Thus, the shop owner has no reasonable chance to expect earning a profit more than $300.

(3)

The expression representing the statement "he'll sell a doughnut to more than half of his coffee customers" is:

<em>Y</em> > 0.5<em>X</em>

<em>Y</em> - 0.5<em>X</em> > 0

Compute the probability of the event (<em>Y</em> - 0.5<em>X</em> > 0) as follows:

P(Y - 0.5X > 0)=P(\frac{(Y - 0.5X) -\mu}{\sigma}>\frac{0-(150-(0.5\times320}{\sqrt{12^{2}+0.5^{2}20^{2}}})\\=P(Z>0.64)\\=1-P(Z

Thus, the probability that the shop owner will sell a doughnut to more than half of his coffee customers is 0.2611.

8 0
3 years ago
What is the range of the following function?
Lelechka [254]

Answer:

Option d

Step-by-step explanation:

Range of a function is the set of y-values for every x-values.

Domain is the set of all values of variable 'x'

From the picture attached,

y-values of the given function varies from negative infinity to positive infinity.

Therefore, range of the function graphed is a set of all real numbers.

Option d is the correct option.

7 0
3 years ago
Solve the equation: 12=102 12 w = 102 .
anyanavicka [17]

Answer:12w=10212w=102.

We move all terms to the left:

12w-(10212w)=0

We add all the numbers together, and all the variables

-10200w=0

w=0/-10200

w=0

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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