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barxatty [35]
3 years ago
13

One gallon of paint covers 400 square feet. What is the least amount of paint needed to paint the walls of a room in the shape o

f a rectangular prism with a length of 20 feet, a width of 16 feet, and a height of 10 feet? Write your answer as a decimal.
Mathematics
1 answer:
Gnom [1K]3 years ago
7 0

Answer:

1.8 gallons would be used.

Step-by-step explanation:

TOTAL AREA TO BE PAINTED:

     2 x 10 x 20  +   2 x10x 16 = 720 ft2

720 ft2 / 400 ft2 /gal = 1.8 gal  

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$500 shared in ratio 2:3:9
RideAnS [48]
2:3:9......added together = 14

2/14 (500) = 1000/14 = 71.43
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The GCF of 148 is what ?
posledela
To find the gcf you need two numbers
8 0
3 years ago
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LAST QUESTION NEED HELP PLEASE
Licemer1 [7]

Answer:

g(x)= (x+8)^2 +2

Step-by-step explanation:

f(x) = x^2

We want to translate it 8 units to the left

h(x) = f(x+8)

h(x) = (x+8)^2

We also want to translate up 2 units

g(x) = h(x) +2

g(x)= (x+8)^2 +2

4 0
4 years ago
Find the distance between the points (-3, 11) and (5,5).<br> O 10<br> 2/10<br> o 2.17
german

Answer: d = 10

Step-by-step explanation:

Step-by-step explanation:

The formula for calculating distance between two points is given by :

d = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

x_{1} = -3

x_{2} = 5

y_{1} = 11

y_{2} = 5

substituting the values , we have

d = \sqrt{(5-(-3))^{2}+(5-11)^{2}}

d = \sqrt{(5+3)^{2}+(-6)^{2}}

d = \sqrt{(8)^{2}+(-6)^{2}}

d = \sqrt{64+36}

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4 0
3 years ago
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What is the range of the following function:<br> y = 2(5^x) - 1
Orlov [11]
<h2>Hello!</h2>

The answer is:

The range of the function is:

Range: y>2

or

Range: (2,∞+)

<h2>Why?</h2>

To calculate the range of the following function (exponential function) we need to perform the following steps:

First: Find the value of "x"

So, finding "x" we have:

y=2(5^{x}-1)\\\frac{y}{2}=5^{x}-1\\\\\frac{y}{2}-1=5^{x}\\\\Log_{5}(\frac{y}{2}-1)=Log_5(5^{x})\\\\x=Log_{5}(\frac{y}{2}-1)

Second: Interpret the restriction of the function:

Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.

So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.

Hence, the range of the function is:

Range: y>2

or

Range: (2,∞+)

Note: I have attached a picture (the graph of the function) for better understanding.

Have a nice day!

5 0
3 years ago
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