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3 years ago

Using static equilibrium calculations, calculate the length from the fulcrum to the

Mathematics

1 answer:

Kisachek [45]3 years ago

3 0

Answer:

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Match the given equation with the verbal description of the surface:

san4es73 [151]

Match of the equation with the verbal description of the surface would be :

Equation 1 = C. plane

Equation 2 = F. Circular cylinder

Equation 3 = C. plane

Equation 4 = E. sphere

Equation 5 = A. cone

Equation 6 = E. Sphere

Equation 7 = F. Circular cylinder

Equation 8 = B. Eliptic or circular paraboloid

Equation 9 = A. cone

Hope this helps

5 0

3 years ago

A developer has 7 1/2 acres of land to build houses on. If each house is to be built on -1/4 acre plot, how many houses can he b

mel-nik [20]

It’s either A.3 or C.30

6 0

3 years ago

Which values are in the solution set of the compound inequality? Select two options

zhannawk [14.2K]

The values are in the solution set of the compound inequality are (-6, -3), (3, 8).

<h3>What is inequality?</h3>

Inequality is the phenomenon of unequal distribution of resources and opportunities among the given function.

To find the number that are solutions to the compound inequalities, the value of x is

First inequality:

4(x +3) ≤0

4x +12 ≤0

4x ≤-12

x ≤-3

The value of x lies in the interval = (-∞ , -3]

Second inequality:

x +1 >3

x>2

The value of x lies in the interval = (2 , ∞)

So, the interval solution is (-∞ , -3] U (2 , ∞)

Thus, the values are in the solution set of the compound inequality are (-6, -3), (3, 8).

Learn more about inequality.

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7 0

2 years ago

Help 5 minutes to turn in

In-s [12.5K]

I think its b not sure

4 0

3 years ago

Read 2 more answers

After being dropped a certain ball always bounces back to 2/5 of the height of its previous bounceAfter the first bounce it reac

kap26 [50]

Answer:

8 inches.

Step-by-step explanation:

In the first bounce, the height that the ball reaches was 125 inches.

If the ball always bounces back to $\frac{2}{5}$ of the height, then after 2nd bounce it will reach $(125 \times \frac{2}{5}) = 50$ inches height.

Again, after 3rd bounce, it will reach $(50 \times \frac{2}{5}) = 20$ inches height.

And, after 4th bounce, it will reach $(20 \times \frac{2}{5}) = 8$ inches height. (Answer)

8 0

3 years ago