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3 years ago

-2+0=? pleaseee help 10pointsss

Mathematics

2 answers:

Luba_88 [7]3 years ago

8 0

-2 is the correct answer.

NikAS [45]3 years ago

5 0

The answerrrrrrrrrrrrrr is -2

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Al Bank is worried about financing of his new home. The house sells for $490,000. If he puts down 20 percent, what will Al's mon

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The answer is A,
how much interest:3675

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3 years ago

What is a solution to (x + 6)(x + 2) = 60?

Reika [66]

Solution of the equation $(x+6)(x+2)=60$ is x=4 and x=-12

Step-by-step explanation:

We need to solve the equation: $(x+6)(x+2)=60$

Solving:

$(x+6)(x+2)=60$

Multiplying terms on the left hand side

$x(x+2)+6(x+2)=60$

$x^2+2x+6x+12=60$

$x^2+8x+12=60$

$x^2+8x+12-60=0$

$x^2+8x-48=0$

Now factorizing:

$x^2+12x-4x-48=0$

$x(x+12)-4(x+12)=0$

$(x-4)(x+12)=0$

$(x-4)=0\,\,and\,\,(x+12)=0$

$x=4\,\,and\,\,x=-12$

So, solution of the equation $(x+6)(x+2)=60$ is x=4 and x=-12

Keywords: Solving Equations

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3 years ago

What is the perimeter of 16cm 25cm

Cloud [144]

Im guessing this is a rectangle? If so it would be
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32+50
82 is the perimeter

4 0

3 years ago

Read 2 more answers

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

5 0

3 years ago

Consider this system of linear equations:

Hatshy [7]

I believe the answer is D. because -12 + -1 equal -13

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3 years ago