Answer:
Are there two you're asking for?
#2: x ≥ 9
#3: x > -2
Step-by-step explanation:
#2 Work:
x - 13 ≥ -4
Step 1: Add 13 to both sides
x - 13 + 13 ≥ -4 + 13
Add -4 and 13 to get 9.
x ≥ 9
#3 Work:
x/2 > -1
Multiply both sides by 2. Since 2 is positive, the inequality direction remains the same
x/2 * 2 > -1 * 2
x > -2
<span>Volume of the Sphere V = 4/3pi x r^3
So when diameter d = 3 inches => r = 1.5 inches
volume of the sphere = 4.188 x r^3 = 4.188 x 1.5^3 = 14.14 in
So when diameter d = 8 inches => r = 4 inches
volume of the sphere = 4.188 x r^3 = 4.188 x 4^3 = 268.03 in
So when diameter d = 9 inches => r = 4.5 inches
volume of the sphere = 4.188 x r^3 = 4.188 x 4.5^3 = 381.63 in
value for option (a) is 3 x 14.14 = 42.42 inches
value for option (b) is 268.03 inches
value for option (c) is 381.63 / 2 = 190.815 inches
So the correct option would be (b)</span>
Answer:
![\frac{1}{6}=0.16](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%3D0.16)
Step-by-step explanation:
Given : There are six balls in bag
Basketballs=2
Playground balls =3
Soccer ball =1
To Find : the probability that if you pick one of the balls without looking, it will be a soccer ball
Solution :
Total no. of balls = 6
No. of soccer balls = 1
Probability = favorable outcomes / total outcomes
Since total outcomes = total no. of balls =6
And favorable outcome = no. of soccer balls = 1
Thus , Probability of getting soccer ball = ![\frac{1}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D)
Hence the probability that if you pick one of the balls without looking, it will be a soccer ball:
![\frac{1}{6}=0.16](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%3D0.16)
Standard equation of a circle: <em>(x-h)² + (y-k)² = r²</em> where <em>(h, k)</em> is the center and <em>r </em>is the radius. In the case of our equation here, <em>(x-5)² + (y+3)² = 25</em>, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.
We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.
Distance =
![\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28y_2-y_1%29%5E2%2B%28x_2-x_1%29%5E2%7D)
Distance =
![\sqrt{(-3-3)^2+(5-2)^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-3-3%29%5E2%2B%285-2%29%5E2%7D)
Distance =
![\sqrt{(-6)^2+3^2}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-6%29%5E2%2B3%5E2%7D)
Distance =
![\sqrt{36+9}](https://tex.z-dn.net/?f=%5Csqrt%7B36%2B9%7D)
Distance =
![\sqrt{45}\approx6.7082](https://tex.z-dn.net/?f=%5Csqrt%7B45%7D%5Capprox6.7082)
The answer is 12 i have answered a question just like dis disrigard the 1 and the genres just add the total number of cds