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yanalaym [24]
3 years ago
14

Find the probability that a number chosen at random from the integers between 5 and 16 inclusive is a multiple of 3 or a mutiple

of 2
​
Mathematics
1 answer:
Neko [114]3 years ago
5 0

Answer: Numbers between 5 and 16 are:-

6, 7, 8, 9, 10, 11, 12, 13, 14 , 15 and 16.

Therefore, total number of outcomes =11

Numbers inclusive between 5 and 16 which are divisible by 2 or 3 are-

6 , 8, 9 ,10 ,12, 14 and 15.

Number of favourable outcomes = 7

Therefore, probability of getting a number which is either a multiple of 2 or 3 is:

p(e) = \frac{7}{11}p(e)=

11

7

HENCE, THE REQUIRED PROBABILITY IS = 7 / 11.

Step-by-step explanation: does this help?

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Solve for x. Round to the nearest tenth, if necessary.
DENIUS [597]

Answer:

x=3.5 cm

Step-by-step explanation:

90/2 = 45 degrees

Soh Cah Toa

We have opposite and hypotenuse making sin.

Length×Sin(Angle)

5×Sin(45) = 3.53553cm

Rounded the the nearest tenth makes 3.5cm

6 0
3 years ago
Is this right yes or no
damaskus [11]

Answer:

i am just a little confused but so far its a yes

Step-by-step explanation:

6 0
3 years ago
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what is the length, in units, of the hypotenuse of a right triangle if each of the two legs is 3 units? square root of 18 units
AfilCa [17]

Answer:

Option 1 is correct that is square root of 18.

Step-by-step explanation:

We will use pythagoras theroem to find the length of hypotenuse

c^2=a^2+b^2

Here, c is hypotenuse,a is one leg and b is the other leg.

Here, a=b=3

On substituting the values in the formula we get:

c^2=3^2+3^2=18

c=\sqrt{18}

Hence, Option 1 is correct that is square root of 18.

8 0
3 years ago
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-23/6 - 7/3=? explain please​
vlabodo [156]

Answer:

37/6

Step-by-step explanation:

-23/6 - 7/3

= -23/6 - 14/6 just make both have the same denominator (2x the 3 to make 6 and do same with numerator)

= 37/6 or 6 1/6

8 0
3 years ago
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Find the first four terms for the arithmetic sequence given a1 = 6 and d = 5
DENIUS [597]

Answer:

6, 11, 16, 21

Step-by-step explanation:

To obtain the first 4 terms add the common difference 5 to the previous term, that is

a₁ = 6

a₂ = a₁ + 5 = 6 + 5 = 11

a₃ = a₂ + 5 = 11 + 5 = 16

a₄ = a₃ + 5 = 16 + 5 = 21

7 0
3 years ago
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