Question

A polynomial P has zeros when x=0, x=-1/6 and x=-3 Whats could be the equation p?

Answer 1

Answer:

P(x) = $x^{3}$ + $\frac{19}{6} x^{2}$ + $\frac{1}{2} x$

Step-by-step explanation:

x(x + 1/6)(x + 3) = P

x($x^{2}$ + 3x + 1/6(x) + 1/2) = P

x ($x^{2}$ + 19/6(x) + 1/2) = P

$x^{3}$ + $\frac{19}{6} x^{2}$ + $\frac{1}{2} x$ = P(x)