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Dmitry [639]
3 years ago
7

This scatter plot and line of best fit show the relationship between the height and the mass of 15 different dog breeds. The cir

cled point in the scatter plot corresponds to the Afghan Hound. What conclusion can be drawn about the predicted mass and the actual mass of the Afghan Hound?
Mathematics
2 answers:
denis-greek [22]3 years ago
6 0

Answer:

The mass of the Afghan Hound is exactly what is predicted by the line of best fit.

ZanzabumX [31]3 years ago
6 0

Answer:

no clue i came to recieve answers

Step-by-step explanation:

You might be interested in
Please EXPLAIN
11111nata11111 [884]

Answer:

<u>The correct answer is 58 1/2 feet. See below to understand the difference of both methods.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the question using both methods:

Area of each student = 4 1/2 square feet

Number of students = 13

2. Let's use the first method to solve the question:

4 1/2 = 9/2 (Improper fraction because the numerator, 9 is bigger than the denominator, 2)

9/2 * 13 = 117/2

<u>117/2 = 58 1/2 square feet</u>

3. Let's use the second method to solve the question:

4 1/2 = 4 + 1/2 (Using addition to rewrite the fraction)

(4 + 1/2) * 13 = (4 * 13) + (1/2 * 13) (Distributive property of the multiplication)

(4 * 13) + (1/2 * 13) = 52 + 13/2 = 52 + 6 1/2

<u>52 + 6 1/2 = 58 1/2 square feet</u>

5 0
3 years ago
A storage shed is to be built in the shape of a (closed) box with a square base. It is to have a volume of 150 cubic feet. The c
Alenkinab [10]

Answer:

C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}

Step-by-step explanation:

We are given the following in the question:

A storage shed is to be built in the shape of a (closed) box with a square base.

Volume = 150 cubic feet

Let s be the edge of square base and h be the height.

Volume of cuboid =

l\times b\times h

where l is the length, b is the base and h is the height.

Volume of box =

s^2h = 150\\\\h = \dfrac{150}{s^2}

Area of base =

\text{side}\times \text{side} = s^2

Cost of concrete for the base = $4

Cost of base($) = 4s^2

Area of roof =

\text{side}\times \text{side} = s^2

Cost of material for the roof = $2

Cost of roof ($) = 2s^2

Area of 4 walls =

4\times (sh)\\=4sh

Cost of material for the side = $2.50

Cost of material of side($) =

2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}

Total cost

= Cost of base + Cost of 4 sides + Cost of roof

C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}

is the required cost function.

5 0
3 years ago
1. Given that ADEF<br> AABC, determine the length of side DF.<br> A<br> 15
marta [7]

Answer:

DEF/3 = BAC

AC(7) x 3 = 21

4 0
2 years ago
Please help me this is for 95 points ​
uranmaximum [27]
Y=12
The angles are 45°, 114°,105°,96° & 84°
7 0
2 years ago
For each value of y , determine whether it is a solution to -21=6y-9 . A -5, B 3 , C -2, D 9
Nezavi [6.7K]

Option C

For each value of y, -2 is a solution of -21 = 6y - 9

<u>Solution:</u>

Given, equation is – 21 = 6y – 9  

We have to find that whether given set of options can satisfy the above equation or not

Now, let us check one by one option

<em><u>Option A) </u></em>

Given option is -5

Let us substitute -5 in given equation

- 21 = 6(-5) – 9

- 21 = -30 – 9  

- 21 = - 39  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option B)</u></em>

Given option is 3

- 21 = 6(3) – 9  

- 21 = 18 – 9  

- 21 = 9  

L.H.S ≠ R.H.S ⇒ not a solution

<em><u>Option C)</u></em>

Given option is -2

- 21 = 6(-2) – 9  

- 21 = - 12 – 9  

- 21 = - 21  

L.H.S = R.H.S ⇒ yes a solution

<em><u>Option D)</u></em>

- 21 = 6(9) – 9

- 21 = 54 – 9  

- 21 = 45  

L.H.S ≠ R.H.S ⇒ not a solution

Hence, the solution for the given equation is – 2, so option c is correct

6 0
3 years ago
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