we have point (-6, - 1)
Now we will put these points in each equation,
y = 4x +23
put x = -6 and y = -1
-1 = 4 (-6) +23
-1 = -24 + 23
-1 = -1
LHS = RHS, so this equation has (-6 , -1) as solution.
y = 6x
put x = -6 and y = -1
-1 = 6 (-6)
-1 not= -36
LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,
y = 3x - 5
put x = -6 and y = -1
-1 = 3 (-6) - 5
-1 = -18 - 5
-1 not= -23
LHS is not equal RHS, so (-6 , -1) is not a solution for that equation,
y= 1/6 x
put x = -6 and y = -1
-1 = -6/6
-1 = -1
LHS = RHS, so (-6 , -1) is a solution for that equation,
97+x=27+64
x=27+64-97
x=-6
(Hopefully this is correct)
Answer:
solution set of f(x) = g(x) is x∈{0,1}
Step-by-step explanation:
For all exponential functions b^x,
b^0 is always 1, and b^1 is always b.
f(x) = -3/4 x + 2
g(x) = (1/4)^x + 1
g(0) = 2, f(0) = 2
g(1) = 5/4, f(1) = 5/4
Answer:
Step-by-step explanation:
two step equation
n - 5/2 = 5
n = 5 + 5/2
n = 5 + 2.5
n = 7.5
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check
7.5 - 5/2 = 5
7.5 - 2.5 = 5
5 = 5
the answer is good
