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ivanzaharov [21]
3 years ago
11

The table shows the purchases made by two customers at a meat counter. You want to buy 2 pounds of sliced ham and 3 pounds of sl

iced turkey. Can you determine how much you will pay? Explain.​

Mathematics
1 answer:
vovikov84 [41]3 years ago
3 0

Answer:

No

Step-by-step explanation:

The equations have infinitely many solutions, so you cannot determine the cost of each meat.

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A 14.5-gallon gasoline tank is $\frac{3}{4}$
LekaFEV [45]
The answer is in the image. We need 3.625 gallons to fill the tank.

6 0
3 years ago
Fiona is pricing two bicycles one is 175 with 10% and the other is 225 with 35% off which bicycle can she afford if she has 150
Gekata [30.6K]
If the one for $175 is 10% off, that means Fiana pays 90% of the price

175 * 0.9 = $157.50

It is too expensive because 157.50 is more than the 150 Fiana has.

The second bike for $225 is 35% off which means Fiana pays 65% of the price.

225 * 0.65 = $146.25

She CAN afford the bike for $225
5 0
3 years ago
Read 2 more answers
The sum of the measures of angle Y and angle Z is 180 degrees. Angle Y measures (3x + 20) degrees and Angle Z measures x degrees
Minchanka [31]
A)
The question tells us that
y + z = 180
And
y=3x+20
z=x

So we put them in the first formula:

y + z = 180
(3x + 20) + x = 180

Add and get x to one side:
4x + 20 = 180
4x + 20 - 20 = 180-20
4x = 160
Divide both sides by 4
x = 40

B)
Put x back in to equation to get size of each angle:

Y =3x +20
Y=3(40)+20
Y=120+20
Y=140

Z=x
Z=40

Verify: y+z=180
140+40=180
180=180
8 0
3 years ago
Which of the following operations is true regarding relative frequency distributions? Multiple choice question. No two classes c
pshichka [43]

Answer:

The relative frequency is found by dividing the class frequencies by the total number of observations

Step-by-step explanation:

Relative frequency measures how often a value appears relative to the sum of the total values.

An example of how relative frequency is calculated

Here are the scores and frequency of students in a maths test

Scores (classes)              Frequency                Relative frequency

0 - 20                                10                               10 / 50 = 0.2

21 - 40                               15                               15 / 50 = 0.3

41 - 60                               10                               10 / 50 = 0.2

61 - 80                                5                                 5 / 50  = 0.1

81 - 100                             <u> 10</u>                                10 / 50 = <u>0.2</u>

                                          50                                               1

From the above example, it can be seen that :

  1. two or more classes  can have the same relative frequency
  2. The relative frequency is found by dividing the class frequencies by the total number of observations.
  3. The sum of the relative frequencies must be equal to one
  4. The sum of the frequencies and not the relative frequencies is equal to the number of observations.

4 0
3 years ago
If x2 - 6x - 16, what are the x-intercepts?​
romanna [79]
If that’s meant to be x^2 - 6x - 16
Then factorise to (x+2)(x-8)
So x intercepts are -2 and 8
8 0
3 years ago
Read 2 more answers
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