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ivanzaharov [21]

2 years ago

11

The table shows the purchases made by two customers at a meat counter. You want to buy 2 pounds of sliced ham and 3 pounds of sl

iced turkey. Can you determine how much you will pay? Explain.

1 answer:

vovikov84 [41]2 years ago

3 0

Answer:

No

Step-by-step explanation:

The equations have infinitely many solutions, so you cannot determine the cost of each meat.

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Sam bought a soft drink for 4 dollars and 7 candy bars . he spent a total of 18 dollars. how much did each candy bar cost?

Masteriza [31]

18 dollars - 4 dollars for the drink = 14 dollars after you take out the drink
$14 divided by 7 candy bars = $2 per candy bar

8 0

3 years ago

Acellus. Solve for x. x = ?

Makovka662 [10]

Answer:

according to basic proportionality theorem

$\qquad\sf {:}\longrightarrow 25/35=x/63$

$\qquad\sf {:}\longrightarrow 5/7=x/63$

$\qquad\sf {:}\longrightarrow 7x=63×5=315$

$\qquad\sf {:}\longrightarrow x=315/7=45$

5 0

2 years ago

Write an equivalent expression for the following

Llana [10]

Answer:

6x, 2x + 4, 5y + 11

Step-by-step explanation:

x + x + x + 2x + x = 6x

(x + 2) + (x + 2) = 2x + 4

y + y + y + y + 10 + y + 1 = 5y + 11

6 0

2 years ago

Use elimination to solve 3x-2y=24 x+2y=48

MakcuM [25]

Answer:

X= 18; Y=15

Step-by-step explanation:

As a student myself working this out I cannot explain how I got the answer but I know it is correct.

5 0

3 years ago

Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .

Solving for F(s) on the last equation, $F(s)=\frac{s}{s^2+25}$ , then the Laplace transform we were searching is $-F'(s)=\frac{s^2-25}{(s^2+25)^2}$

3 0

2 years ago