The graph of f(x)= 5x is reflected across the x-axis. Write a function g(x) to describe the new graph. g(x)=

One day when Terry went to school the temperature outside was –15 degrees Fahrenheit. In Terry's classroom the temperature was 6

Dominik [7]

Well, to find the answer to this problem you have to change the -15 to a positive (+15) and add the two numbers together. And, 15 + 68 = +83 degrees.

So, your answer is: A. +83 degrees.

It's really easy because all your doing is changing the -15 to a positive 15 and adding the two numbers together to get your answer.

Hope I helped!

- Debbie

7 0

2 years ago

Read 2 more answers

1 15/100 + 1/50 +1.175=

grin007 [14]

$1\frac{15}{100}+\frac{1}{50}+1.175 =\frac{115}{100}+\frac{1}{50}+1.175 =\frac{23}{20}+\frac{1}{50}+1.175 =\frac{115}{100}+\frac{2}{100} =\frac{115}{100}+\frac{2}{100} =\frac{115+2}{100} =1.175+\frac{117}{100} =1.175+1.17 =2.345$

<h3><em>You can write </em> $2.345$ <em> or </em> $2\frac{69}{200}$ <em></em></h3><h3><em></em></h3><h3><em>Hope I helped you!</em></h3><h3><em>Success!</em></h3>

6 0

2 years ago

An airplane has 100 seats for passengers. Assume that the probability that a person holding a ticket appears for the flight is 0

zmey [24]

Answer:

96.33% probability that everyone who appears for the flight will get a seat

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .