<span>A diagonal cross section of a sphere produces a circle.
Regardless of how the sphere is cut, it will form a circle.
</span>
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Suppose :
2^x = t ..**&**.. 3^y = u
_____________________________
t + u = 9 × 3 3t + 3u = 27
=====》
2t - 3u = 8 2t - 3u = 8
+ __________
5t = 35
5 × t = 5 × 7
t = 7
&
u = 2
________________________________
Thus :
2^x = 7 ===》 x = Log _ 2 { 7 }
3^y = 2 ===》 y = Log _ 3 { 2 }
(x - 4)(2x + 3)
Using foil:
2x^2 + 3x - 8x - 12
Simplify.
2x^2 - 5x - 12 is the product after using FOIL.
Answer:
The time taken for the projectile to reach the given height is 1.2 s.
Step-by-step explanation:
Given;
height of travel, h = 25 ft
initial velocity of the projectile, u = 15 ft/s
The time taken for the projectile to travel a height of 25 ft is given by the following kinematic equation;
h = ut + ¹/₂gt²
25 = 15t + ¹/₂(9.8)t²
25 = 15t + 4.9t²
4.9t² + 15t - 25 = 0
solving the quadratic equation, we will have the following solution of t;
t = 1.2 s
Therefore, the time taken for the projectile to reach the given height is 1.2 s.
Answer:140 over 3
Step-by-step explanation: i got that answer but i dont think its the right
