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serious [3.7K]
3 years ago
12

Determine if the two lines y=2x-3/2 and y=-2x+2/3 are parallel, perpendicular or neither

Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0
They’re both perpendicular, I used a graphing calculator to get the interpret answer
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Solve this system of linear equations. Separate
Elanso [62]

Answer:

(-3, -3)

Step-by-step explanation:

1.) Rewrite the second equation so 3y is on one side of the equation:

3y=6+5x

2.) Substitute the given value of 3y (replacing 3y with 6+5x, since we know they equal each other) into the equation 17x=-60-3y

Should end up with this:

17x=-60-(6+5x)

3.) Solve 17x=-60-(6+5x)

Calculate Difference: 17x=-66-5x

Combine Like Terms: 22x = -66

Divided both sides by 22 to isolate and solve for x: -3

So We know x=-3, now we got to find the y value. We can use either the first or second equation to find y value, so lets use the second.

3y=6+5x

1.) We know that x=-3, so we can simply substitute x in the equation

3y=6+5x with -3

3y=6+5(-3)

2.) Solve 3y=6+5(-3)

Combine Like Term: 3y=6+-15

Combine Like Term Even More: 3y= -9

Divide by 3 on both sides to isolate and solve for y: y=-3

So now we know y=-3 and once again we know x=-3, so if we format that

(-3,-3)

^  ^

x  y

4 0
3 years ago
What is 2906 to the nearest thousand
OlgaM077 [116]
It is equal to 3000 to the nearest thousandth

3 0
3 years ago
Read 2 more answers
What is the inverse of the function fx) x +3?
xz_007 [3.2K]
<span>My answer -
f(x)=x^3+2 To find the inverse function f(x)^-1 , we will assume" y=x^3+2 y-2= x^3 ==> x= (y-2)^1/3 ==> f(x)-1= (x-2)^1/3</span>
P.S

Happy to help you have an AWESOME!!!!! day
6 0
3 years ago
10 - 7w - 13 - 7w + 15
Debora [2.8K]

Answer:

-14w+12

Step-by-step explanation:

10 - 7w - 13 - 7w + 15

Combine like terms

- 7w  - 7w + 10-13+15

-14w+12

4 0
2 years ago
Prove that an = 4^n + 2(-1)^nis the solution to
olga nikolaevna [1]

Answer:

See proof below

Step-by-step explanation:

We have to verify that if we substitute a_n=4^n+2(-1)^n in the equation a_n=3a_{n-1}+4a_{n-2} the equality is true.

Let's substitute first in the right hand side:

3a_{n-1}+4a_{n-2}=3(4^{n-1}+2(-1)^{n-1})+4(4^{n-2}+2(-1)^{n-2})

Now we use the distributive laws. Also, note that (-1)^{n-1}=\frac{1}{-1}(-1)^n=(-1)(-1)^{n} (this also works when the power is n-2).

=3(4^{n-1})+6(-1)^{n-1}+4(4^{n-2})+8(-1)^{n-2}

=3(4^{n-1})+(-1)(6)(-1)^{n}+4^{n-1}+(-1)^2(8)(-1)^{n}

=4(4^{n-1})-6(-1)^{n}+8(-1)^{n}=4^n+2(-1)^n=a_n

then the sequence solves the recurrence relation.

4 0
3 years ago
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