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2 years ago

6

Can anyone help pllllzzzz

1 answer:

Sladkaya [172]2 years ago

4 0

Answer:

Muercury 3

Venus 6

Mars 2

pluto 5

Jupiter 1

Nucleus4

Step-by-step explanation:

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Substation method x-2y=5 ,<br> 3x-5y=8

valina [46]

$x-2y=5 \\
3x-5y=8 \\ \\
\hbox{solve the first equation for x:} \\
x-2y=5 \ \ \ |+2y \\
x=2y+5 \\ \\
\hbox{substitute 2y+5 for x in the second equation:} \\
3(2y+5)-5y=8 \\
6y+15-5y=8 \\
y+15=8 \ \ \ |-15 \\
y=-7 \\ \\
x=2y+5=2 \times (-7)+5=-14+5=-9 \\ \\
\boxed{(x,y)=(-9,-7)}$

6 0

3 years ago

Use the formula P = 2l + 2w. Find the perimeter of a rectangle with a length of 12.9 ft and a width of 19.3 ft.

vovikov84 [41]

The answer is P= 64.4 hope it helped

6 0

3 years ago

What is the missing value? The Volume is 5120 m^3

Neko [114]

I think that the missing value is 16m.

I just multiplied two other numbers with 20 and 20 x 16 x 16 = 5120

I hope this was right.

7 0

3 years ago

Hiran invests 20 000 rupees in an account for 3 years at 1.5% per year compound interest.

svp [43]

Answer:

There will be 20 914 rupees in the amount at the end of 3 years.

Step-by-step explanation:

The amount of rupes after t years in compound interest is given by:

$A(t) = A(0)(1+r)^{t}$

In which A(0) is the initial amount and r is the interest rate, as a decimal.

Hiran invests 20 000 rupees in an account for 3 years at 1.5% per year compound interest.

This means that $A(0) = 20000, r = 0.015$ . So

$A(t) = A(0)(1+r)^{t}$

$A(t) = 20000(1+0.015)^{t}$

$A(t) = 20000(1.015)^{t}$

Work out the total amount of money in the account at the end of 3 years.

This is A(3). So

$A(3) = 20000(1.015)^{3} = 20913.6$

Rounding to the nearest rupee.

There will be 20 914 rupees in the amount at the end of 3 years.

8 0

2 years ago

Researchers counted 8,912 monarch butterflies on one branch however estimated that number to be 1,000 times as large.

azamat

Okay and what is the question you are asking?

3 0

3 years ago