Answer: No, it is not possible
A triangle can only have 1 obtuse interior angle, leaving the exterior angle next to it to be acute. For example, if you have an interior angle of 120 (obtuse) then the adjacent exterior angle is 60 (acute)
The other two interior angles must be acute if you go with 1 obtuse angle, which leaves the corresponding exterior angles to be obtuse. If you wanted the exterior angles to be all acute, then you would need 3 obtuse interior angles, but that is not possible.
Why isn't it possible to have 3 obtuse angles? Consider a triangle with interior angles A, B, C. The three angles must add to 180
A+B+C = 180
If A,B,C were all larger than 90, then
A > 90
B > 90
C > 90
A+B+C > 90+90+90
A+B+C > 270
but that contradicts A+B+C being equal to 180
Take both mixed numbers (a whole number plus a fraction) and turn them into improper fractions ( a numerator (top number) bigger than the denominator (bottom number). To do this, multiply the denominator by the whole number, and add the result to the numerator.
5 5/8 will become 45/8
1 1/2 will become 3/2.
Area is length* width, so width would be Area/ length. So 45/8 is the area and 3/2 is the length. Now you have (45/8)/(3/2). To divide fractions, take the second fraction and flip the numerator and denominator, forming the reciprocal (2/3). Now multiply 45/8 and 2/3
The result is 90/24, and simplifying would get 15/4, or 3 3/4. This is the width(or length)
It would increase the average, just by a bit.
Hello !
You have to do as follow :
