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Misha Larkins [42]
4 years ago
15

GIVEN THE FUNCTION F(X) =3X + 5 AND X SUCH THAT F(X)=38

Mathematics
1 answer:
umka21 [38]4 years ago
6 0

The value of X is 11.

<u>Step-by-step explanation</u>:

Given,

  • F(X) = 3X + 5   --------(1)
  • F(X) = 38    ------------(2)

Equating eq(1) and (2),

⇒ 3X+5 = 38

⇒ 3X = 38-5

⇒ X = 33/3

⇒ X = 11

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Phoenix [80]
The answers is 11x+2 I’m pretty sure. I can’t tell if your x3 was an exponent or multiplying.
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A group of scientist study the effect of chemical on Various strains of bacteria. Strain A started with 6000 cells and decreases
miskamm [114]
After h hours A has 6000 - 2000h cells and B has 2000 - 1000h. Equating them as one form:
6000 - 2000h = 2000 - 1000h
-2000h + 1000h = 2000 - 6000
-1000h = -4000
h = -4000/-1000 = 4 hours

4 0
3 years ago
1. What is x squared over 6=w-y if the subject of the formula is x??? Help please
Kay [80]
\frac{x^2}{6}=w-y\\&#10;x^2=6(w-y)\\&#10;x=\sqrt{6(w-y)} \vee x=-\sqrt{6(w-y)}
8 0
3 years ago
Read 2 more answers
Nine times a number decreased by 16
Setler79 [48]

Answer:

9 · x - 16

Explanation:

Nine times a number: 9 · x

Decreased by 16: - 16

Put them together: 9 · x - 16

7 0
3 years ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
anastassius [24]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

It is clear that h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

4 0
3 years ago
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