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3 years ago

Does anyone know what 3x+y=15 5x3y=11 is? It has to be answered in desmos.

Mathematics

1 answer:

faust18 [17]3 years ago

8 0

3x + y = 15

5x3y = 11

This is an example of a system of equations.

A system of equations is two or more equations that can be graphed, as the solution that satisfies both equations will be the point where the lines intersect on a graph.

Desmos is a graphing calculator, and thus it allows you to visualize this system.

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How do you find a variable to 4-2(v+9)=26

garik1379 [7]

Answer:

V=20

Step-by-step explanation:

Simplify both sides of the equation.

4−2(v+9)=26

4+(−2)(v)+(−2)(9)=26(Distribute)

4+−2v+−18=26

(−2v)+(4+−18)=26(Combine Like Terms)

−2v+−14=26

−2v−14=26

Step 2: Add 14 to both sides.

−2v−14+14=26+14

−2v=40

Step 3: Divide both sides by -2.

−2v

−2

v=−20

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3 years ago

A point with coordinates (a, b) is plotted on a coordinated plane. The values of a and b can be any positive or negative integer

Diano4ka-milaya [45]

Answer:

Any negative and positive number can be your coordinates.

Step-by-step explanation:

As long as you don't have any restrictions as to what the coordinates can be, you're good to go!

Hope this helps!

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3 years ago

Point H(x,y) moves 12 units left and 4 units up. What is a rule that describes this translation?

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The x values decrease by 12 and the y increase by 4.

Answer: (x-12, y+4)

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3 years ago

Who are the rivals in the poem.?

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3 years ago

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

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3 years ago