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3 years ago

Does anyone know what 3x+y=15 5x3y=11 is? It has to be answered in desmos.

Mathematics

1 answer:

faust18 [17]3 years ago

8 0

3x + y = 15

5x3y = 11

This is an example of a system of equations.

A system of equations is two or more equations that can be graphed, as the solution that satisfies both equations will be the point where the lines intersect on a graph.

Desmos is a graphing calculator, and thus it allows you to visualize this system.

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A traffic helicopter descends 102 meters to be 331 meters above the ground, as illustrated in the diagram to the right. Write an

lana66690 [7]

Answer:

h -102 = 331
h = 433

Step-by-step explanation:

Using the problem statement as the basis for the equation, we can write ...

h -102 = 331

Using the diagram as the basis for the equation, we could write it as ...

h = 331 +102

The original height of the helicopter was 433 m.

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2 years ago

Consider the graph of the quadratic function y=3x↑2↓-3x-6.what are the solutions of the quadratic equation 0=3x↑2↓-3x-6

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X = 2 or -1

factors to 3(x-2)(x+1)=0

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3 years ago

EMERGENCY! PLEASE HELP! Prism A & Prism B are similar. The volume of prism A is 648 mm^3. If the scale factor of Prism A t

garik1379 [7]

Answer:

$1944 mm^{3}$

Step-by-step explanation:

4 0

3 years ago

Name the prism in each case given that all lateral faces are rectangles and the bases are: Equilateral triangles

Cloud [144]

This is a triangular prism.

The lateral faces are triangles; this means that the two bases are parallel to one another. This makes it a prism instead of a pyramid.

The bases being triangles makes it a triangular prism.

6 0

3 years ago

The height in feet of a baseball can be modeled by the function y=-16t^2+64t where t is the time in

VikaD [51]

Answer:

the ball reaches a height of 64 feet after 2 sec.

The ball is in the air 4 sec.

Step-by-step explanation:

The ball is following the path of a parabola. The maximum height is at the vertex of the parabola.

Let (h, k) be the vertex. h will be the time it takes to reach the maximum height, and k will be that height.

y = $-16t^{2} + 64t$

h = -b/2a = 64/(-2)(-16) = 64/32 = 2

k = -16(2)^2 + 64(2)

-16(4) + 128

- 64 + 128 = 64

V: (2, 64)

So the ball reaches a height of 64 feet after 2 sec.

Let $-16t^{2} + 64t$ = 0 (0 is the height when the balls hits the ground)

-16t(t - 4) = 0

t = 0 or t = 4

The ball is in the air 4 sec.

3 0

3 years ago