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andreev551 [17]
3 years ago
10

Convert 77/200 into a decimal

Mathematics
1 answer:
Marrrta [24]3 years ago
7 0
0.385 because if you divide it, the answer is 0.385
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I will give branlyest 2/11 ≥ 4/25<br><br><br> true false
scZoUnD [109]

Answer:

True.  2/11 is greater than 4/25

Step-by-step explanation:

Hope that helps!

3 0
2 years ago
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Solve |z - 8| = 4 please
bezimeni [28]

Answer:

4

Step-by-step explanation:


5 0
3 years ago
Convert from rectangular to polar coordinates: note: choose rr and θθ such that rr is nonnegative and 0≤θ&lt;2π0≤θ&lt;2π (a)(9,0
DochEvi [55]

Answer:

Step-by-step explanation:

Convert rectangle (x , y) to polar coordinates ( r , θ)

x=r  \cos \theta, y= r \sin \theta

r=\sqrt{x^2+y^2} , \theta =tan^-^1 (\frac{y}{x} )

a) converts (9, 0) to polar coordinates  ( r , θ)

r=\sqrt{x^2+y^2} \\\\=\sqrt{9^2+0} \\\\=9

\theta= \tan^-^1 (\frac{0}{9} )\\\\=0

b) Convert (18,\frac{18}{\sqrt{3} } ) to polar coordinates ( r, θ)

r = \sqrt{18^2+(\frac{18}{\sqrt{3} })^2 } \\\\=\sqrt{324+108} \\\\=\sqrt{432}

\frac{x}{y} \theta = \tan^-^1(\frac{\frac{18}{\sqrt{3} } }{18} )\\\\= \tan ^-^1(\frac{1}{\sqrt{3} } )\\\\= \frac{\pi}{6}

c)  converts (-5, 5) to polar coordinates  ( r , θ)

r =\sqrt{(-5)^2+(5)^2} \\\\=\sqrt{50} \\\\=5\sqrt{2}

\theta=\tan^-^1(\frac{5}{-5} )\\\\= \tan^-^1(-1)\\\\=\frac{3\pi}{4}

d)  converts (-1, √3) to polar coordinates  ( r , θ)

r=\sqrt{(-1)^2+(\sqrt{3})^2 } \\\\= \sqrt{4} \\\\=2

\theta=\tan^-^1(\frac{\sqrt{3} }{-1} )\\\=\tan^-^1(-\sqrt{3} )\\\\=\frac{2\pi}{3}

= \frac{2\pi}{\sqrt{3} }

6 0
3 years ago
Find the length of diagonal AC in the rectangle<br> at the right<br><br> show you’re work plss
ivolga24 [154]

Answer:

26

Step-by-step explanation:

Let 10 be a, and 24 be b, and the undefined hypotenuse be c.

a^2 + b^2 = c^2

10^2 + 24^2 = c^2

100 + 576 =  c

c = 676

\sqrt{100} + \sqrt{576} = \sqrt{676}

10^2 + 24^2 = 26^2

c = 26

The value of the undefined line is 26.

7 0
3 years ago
Solve -np-80&lt;60 for n. Show your work.<br><br> Solve 2a-5d=30 for d. Show your work.
xz_007 [3.2K]

-np-80 < 60\qquad\text{change the signs}\\\\np+80

------------------------------------------------------

2a-5d=30\qquad\text{subtract 2a from both sides}\\\\-5d=-2a+30\qquad\text{change the signs}\\\\5d=2a-30\qquad\text{divide both sides by 5}\\\\d=0.4a-6

8 0
3 years ago
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