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Yuki888 [10]
3 years ago
7

7. The planet Abydos experiences drastic changes in temperature over the course of the day. On one day it reached a minimum temp

erature of −290°F, but then warmed up to a maximum temperature of −100°F.
What was the temperature change that day?
Mathematics
1 answer:
Delicious77 [7]3 years ago
6 0

Answer:

The temprature change was +190 degrees farenheit

Step-by-step explanation:

subtract 290-100 using absolute value

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Find the value of x.
lawyer [7]

Answer:

\huge\boxed{x=\sqrt{70}}

Step-by-step explanation:

ΔABC and ΔADB are similar (AAA).

Therefore the corresponging sides are in proportion:

\dfrac{AB}{AD}=\dfrac{AC}{AB}

Substitute:

AB=x\\AC=7+3=10\\AD=7

\dfrac{x}{7}=\dfrac{10}{x}       <em>cross multiply</em>

(x)(x)=(7)(10)\\\\x^2=70\to x=\sqrt{70}

4 0
3 years ago
Graph -3 and one 3/2 and -0. Five and three on a number line
mina [271]

Answer:

if u want me to be honest i have no clue

7 0
2 years ago
Evaluate 3^2 (6-2) times 4-6/3
dedylja [7]
3^2(6-2)*(4-6)/3
=(9*4)*(-2/3)
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4 0
3 years ago
Plz someone answer this I need the answer quick
pogonyaev

Answer:

<h2>290 m^3</h2>

Solution,

volume = (8 \times 5 \times 5) + (5 \times 6 \times 3) \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 200 + 90 \\  \:  \:  \:  \:  \:   \:  \:  \:  \:  = 290 \:  {m}^{3}

Hope this helps..

Good luck on your assignment..

7 0
3 years ago
Consider the region bounded by
Montano1993 [528]
The equation is a circle centered at the origin with radius 8 (sqrt(64))
Therefore, the bounded region is just a quarter circle in the first quadrant.

Riemann Sum: ∑⁸ₓ₋₋₀(y²)Δx=∑⁸ₓ₋₋₀(64-x²)Δx

Definite Integral: ∫₀⁸(y²)dx=∫₀⁸(64-x²)dx
4 0
3 years ago
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