The excess reactant when 4.35 g of hydrogen reacts with 30.75g of hydrogen iodide is hydrogen
<h3>calculation</h3>
write the equation for the reaction
H2(g) + I2 (g) → 2HI (g)
find the mole of each reactant
moles = mass/molar mass
moles of H2= 4.35 g/2 g/mol= 2.175 moles
moles o I2 = 30.75 g/ 254 g/mo=0.1211 moles
0.1211 moles of I2 reacted with 0.1211 moles of H2 but there are more moles of H2 there Hydrogen was in excess
What makes people wanna come us with these things
The equation which we are required to complete can be completed as follows;
- AgNO3 + KCl ==> KNO3 + AgCl
<h3>Electrochemical series;</h3>
Most substitution reactions involve displacement of metals and non-metals.
The possibility of a substitution reaction to occur is sometimes dependent on the order of preference of the metals in the activity series.
On this note, In the reaction between AgNO3 and KCl, potassium, K displaces silver, Ag and the products of the reaction are; KNO3 and AgCl
Read More on Electrochemical series;
brainly.com/question/14652325
the correct scientist is rutherford
Answer:
*2Kl+Pb(NO3)2=PbI2+2KNO3: double replacement.
*2Al+3CuSO4=Al2(SO4)3+3Cu: single replacement.
*C2H5OH+3O2=2CO2+3H2O: combustion.
Explanation:
Hello there!
In this case, according to the required, it turns out necessary for us to recall the five types of reactions, combination, decomposition, single and double replacement and combustion as shown on the attached figure.
In such a way, since the first reaction follows the pattern AB+CD-->AD+CB we infer it is double replacement; the second reaction follows the patter A+BC-->AC+B and therefore it is single replacement; and the last one follows the pattern of combustion reaction due to the presence of CO2 and H2O on the products side.
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