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larisa [96]
3 years ago
8

Select the correct answer. William buys two bags of peaches and three bags of apricots for $17. Sylvia buys four bags of peaches

and two bags of apricots for $22 from the same store. What is the cost of one bag of peaches?
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
7 0

Answer:

1 bag of peaches costs $4.00

Step-by-step explanation:

\left \ {{y=$3.00} \atop {x=$4.00}} \right.

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3. The temperature of a swimming pool
Anastaziya [24]

Answer:

81 F

Step-by-step explanation:

Hours | Temp.

   0     | 75F

   1      | 77F

   2     | 79F

   3     | 81F

4 0
3 years ago
Which equation has a constant of proportionality equal to three
Andreas93 [3]

Answer in Picture :)

4 0
3 years ago
PLZ HELP FAST shsggsgsgsbdfikand​
OLga [1]

Answer:  

x    y-values

1    175

2   175

3   225

4    275

The domain is 1,2,3,4  it would be from 1 to 4 if the electrician bills for partial hours, or greater than 4, but this is not in the chart.

The range is 175,225,275.  Again there could be other values in between or greater than 275, but it is not in the chart.

Step-by-step explanation:  It is a function because for each x-value there is only one y-value, even if the y-value is the same for two of the x-valus

5 0
3 years ago
What is the LCM and GCF for 15 and 60
slavikrds [6]
LCM of 15 and 60 is 60.

GCF of 15 and 60 is 15.
7 0
3 years ago
Read 2 more answers
Three molecules of type A, three of type B, three of type C, and three of type D are to be linked together to form a chain molec
ipn [44]

Answer:

a) 369,600

b) 0.0000649

Step-by-step explanation:

If all of the A's, B's, C's and D's were different, the number of ways to form a molecule would be calculated as n!. However, given that every molecule is repeat 3 times, we need to reduce the number dividing by 3! for every type of molecule.

It means that the number of ways in which we can organize n elements where not all of them are equal is calculated as:

\frac{n!}{n_1!*n_2!*...*n_k!}

Where k is the number of elements that are differents and n_1,n_2,...,n_k are the number of times that every element appears.

Now, we have 4 different types of molecules (A,B,C,D) so k is equal to 4. Additionally, there are 3 molecules of type A, 3 of type B, 3 of type C, and 3 of type D, so n_1=3, n_2=3, n_3=3 and n_4=3. It means that there are 369,600 ways to form chain molecules and it is calculated as:

\frac{12!}{3!*3!*3!*3!}=369,600

Now, the number of ways where all three molecules of each type end up next to one another is calculated as:

4*3*2*1=24

Because, first we have 4 possible types of molecules to occupy the first three positions, then we have 3 possible types of molecules to occupy the following 3 positions, then we have 2 possible types of molecules and finally we have 1 possible type of molecule

So, the probability that all three molecules of each type end up next to one another is calculated as:

\frac{24}{369600}=0.0000649

6 0
3 years ago
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