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8090 [49]
2 years ago
10

CAN SOMEONE PLEASE HELP

Mathematics
1 answer:
Lorico [155]2 years ago
5 0

Answer:

52 degreesssssssssssssssssss

Step-by-step explanation:

its OVER 9,0000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

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Please help!!!!!<br>Solve the equation 5(2y - 1) - 2(3y)= 1<br>​
-Dominant- [34]

Answer:

y = 3/2

Step-by-step explanation:

5(2y - 1) - 2(3y) = 1

First we use distributive property:

10y - 5 - 6y = 1

because 5 × 2y = 10y

and -2 × 3y = -6y

Now we combine the like terms:

4y -5 = 1

because 10y - 6y = 4y

Now we have to send the -5 to the other side. (when we send it to the other side it becomes positive because right now it is negative)

4y = 1 + 5

Again we combine the like terms:

4y = 6

(because 5 + 1 = 6)

Now we have to send the 4 to the other side because we need to get the y value. (when we send it to the other sidr it will be divided)

y = 6/4

and we simplify:

y = 3/2

And we cannot simplify or do anything else. So that is the answer.

Hope that helped!

5 0
3 years ago
Look at this graph:
Black_prince [1.1K]

Answer:

3/2

Step-by-step explanation:

slope=rise/run=30/20=3/2

3 0
3 years ago
Let the universal set be the set of integers and let A = {x | x^2 ≤ 5}. Write A using the roster method.
Zarrin [17]

Answer:

Step-by-step explanation:

Given that Z the set of integers is the universal set and

A is given in set builder form.

A = {x | x^2 ≤ 5}

To convert this into roster form, we can find solutions for x

When x^2\leq 5\\|x|\leq \sqrt{5} =2.236

i.e. all integers lying between -2.236 and 2.236

The only integers satisfying this conditions are

-2,-1,0,1,2

Hence A in roster form is

A={-2,-1,0,1,2}

8 0
3 years ago
Equation for the given function
Lera25 [3.4K]

Answer:

Step-by-step explanation:

hello :

g(x) = (x+2)(x-4)/(x+2)(x-1)

1 )  this function no exist for if : x= -2 and 1

so the denominater is : (x+2)(x-1)

so : b= 2  and c=1

2) the x- intercept is : 4

so the numerater is : (x+2)(x-4)

g(x) =0 if : (x+2)(x-4)=0

means x-4=0    ...   (  x+2 ≠ 0)

note :

g(x) ≠ (x-4)/(x-1) except in the case  x ≠ -2  

7 0
3 years ago
Abc~def what sequence of transformation will move ABC onto def ​
DENIUS [597]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
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