Answer:
The correct answer is 
Step-by-step explanation:
A fair coin is tossed three times in a succession the sample space is shown where h represents a head and t represents a tail.
Let the experiment A denote that we get exactly one tail in three successive toss of a coin.
Sample space = { hhh, hht, hth, thh, tth, tht, htt, ttt} = 8
Favorable sample = { hht, hth, thh } = 3
Probability of the A = 
= = 0.375.
Thus the probability of getting exactly one tail in three successive toss of a fair coin is given by 0.375
Answer:
Step-by-step explanation:
line segments are taken to line segments of the same length;
angles are taken to angles of the same measure; and.
lines are taken to lines and parallel lines are taken to parallel lines.
Area of the composite shape = 292 yd²
Solution:
The shape is splitted into two rectangles.
The reference image of the answer is attached below.
Length of the top rectangle = 21 yd
Width of the top rectangle = 29 yd – 22 yd = 7 yd
Length of the side rectangle = 29 yd
Width of the side rectangle = 26 yd – 21 yd = 5 yd
Area of the figure = Area of the top rectangle + Area of the side rectangle
= (length × width) + (length × width)
= (21 × 7) + (29 × 5)
= 147 + 145
= 292
Area of the composite shape = 292 yd²
<u>m = 6a + 9ak</u>
On the right side, factor ' 3a ' from the expression:
m = 3a (2 + 3k)
Divide each side by (2 + 3k)
m / (2 + 3k) = 3a
Divide each side by 3 :
<em>m / 3(2 + 3k) = a</em>
Answer:
The number of different lab groups possible is 84.
Step-by-step explanation:
<u>Given</u>:
A class consists of 5 engineers and 4 non-engineers.
A lab groups of 3 are to be formed of these 9 students.
The problem can be solved using combinations.
Combinations is the number of ways to select <em>k</em> items from a group of <em>n</em> items without replacement. The order of the arrangement does not matter in combinations.
The combination of <em>k</em> items from <em>n</em> items is: 
Compute the number of different lab groups possible as follows:
The number of ways of selecting 3 students from 9 is = 
Thus, the number of different lab groups possible is 84.
